var specializationTitles = ["a","b","c","d"]
let outputString = join(" / ",specializationTitles)
发生错误:
Cannot invoke join
with an argument list of type (String,[String])
如何解决这个问题?
let separator = " / "
let outputString = separator.join(specializationTitles)
与Xcode7beta6:
specializationTitles.joinWithString(" / ")
使用Xcode7发布版本:
specializationTitles.joinWithSeparator(" / ")