比较Swift中C函数的指针

我正在寻找一种方法来比较指向c函数的指针.例如.：

let firstHandler = NSGetUncaughtExceptionHandler()

NSSetUncaughtExceptionHandler(onUncaughtException)
let secondHandler = NSGetUncaughtExceptionHandler()

if firstHandler == secondHandler {
    debugPrint("equal")
}

更新==,也不是===有效

在目标C中,我可以表达如下：

NSUncaughtExceptionHandler *firstHandler = NSGetUncaughtExceptionHandler();

NSSetUncaughtExceptionHandler(onUncaughtException);
NSUncaughtExceptionHandler *secondHandler = NSGetUncaughtExceptionHandler();

if (firstHandler == secondHandler) {
    NSLog(@"equal");
}

提前致谢

通常,您无法在Swift中比较函数的相等性.
但是,NSSetUncaughtExceptionHandler返回一个

(@convention(c) (NSException) -> Swift.Void)?

即(可选的)C兼容功能,并且这样的功能可以是
强制转换为(可选)原始指针
unsafeBitCast：

let ptr1 = unsafeBitCast(firstHandler,to: Optional<UnsafeRawPointer>.self) 
let ptr2 = unsafeBitCast(secondHandler,to: Optional<UnsafeRawPointer>.self)

然后可以比较平等

if ptr1 == ptr2 {.. }

一个独立的例子：

func exceptionHandler1(exception : NSException) { }

func exceptionHandler2(exception : NSException) { }

NSSetUncaughtExceptionHandler(exceptionHandler1)
let firstHandler = NSGetUncaughtExceptionHandler()
NSSetUncaughtExceptionHandler(exceptionHandler2)
let secondHandler = NSGetUncaughtExceptionHandler()

let ptr1 = unsafeBitCast(firstHandler,to: Optional<UnsafeRawPointer>.self) 

print(ptr1 == ptr2) // false