如何使用python查找和更新XML文件内容

编程问答 2022-10-28

问题描述

例如

 <managedobject class="New" distName="MB-85404/TB-85404/ST-4/a" version="xL20A_1911_002" operation="open">
          <p name="a">320ms</p>
          <p name="b">enabled</p>
          <p name="c">640ms</p>
          <p name="d">320ms</p>
          <p name="e">640ms</p>
          <p name="f">1280ms</p>
          <p name="g">6</p>
    </managedobject>
<managedobject class="new" distName="AL-76867/MB-85404/TB-85404/ST-4/b" version="xL20A_1911_002" operation="open">
          <p name="h">320ms</p>
          <p name="i">enabled</p>
          <p name="j">640ms</p>
          <p name="k">320ms</p>
          <p name="l">640ms</p>
          <p name="a">1280ms</p>
          <p name="l">6</p>
    </managedobject>
<managedobject class="New" distName="MB-85404/TB-85404/ST-4/c" version="xL20A_1911_002" operation="open">
          <p name="a">320ms</p>
          <p name="p">enabled</p>
          <p name="q">640ms</p>
          <p name="r">320ms</p>
          <p name="s">640ms</p>
          <p name="t">1280ms</p>
          <p name="u">6</p>
    </managedobject>

在此示例中，我首先要将(distName="MB-85404/TB-85404/ST-4/[a or b or c]")更新为(distName="MB-85409/TB-85409/ST-4/[a or b or c]")

对整个XML文件执行此操作之后。

执行完此操作后，我想更新标签name="a"的值<managedobject class="New" distName="MB-85409/TB-85409/ST-4/[a or b or c] >

如何执行此操作，我有一个40000多行的XML文件。

EDIT1 

with open("C:/files/abcd.xml","w+") as file:
    xml_data = file.read()
    xml_data.replace("85409","85904")
    file.write("outPuta.xml")

EDIT2 

soup = bs(content,"xml")
    loc = re.compile(r'[A-Z]+-+[0-9]+/+SMOD+-+[1-9]')
    for i in soup.find_all('managedobject',distName=loc):
        locat=i.find('p',{'name':'moduleLocation'})
        locat.string="3444 South texas"

通过此代码，我试图找到与distname匹配的regex loc，并且在managedobject内，我试图找到标签<p name="moduleLocation" 4444 New York>，并且我想更新{{1 }}到"4444 New York"，这给了我下面提到的错误

"3444 South texas"

解决方法

希望我能正确理解您的问题，这将找到所有distName="MB-85404/TB-85404/ST-4/[a or b or c]"标签并将85404替换为85409，并更新<p name="a">标签：

import re
from bs4 import BeautifulSoup


xml_data = ''' <managedObject class="New" distName="MB-85404/TB-85404/ST-4/a" version="xL20A_1911_002" operation="open">
          <p name="a">320ms</p>
          <p name="b">enabled</p>
          <p name="c">640ms</p>
          <p name="d">320ms</p>
          <p name="e">640ms</p>
          <p name="f">1280ms</p>
          <p name="g">6</p>
    </managedObject>
<managedObject class="new" distName="AL-76867/MB-85404/TB-85404/ST-4/b" version="xL20A_1911_002" operation="open">
          <p name="h">320ms</p>
          <p name="i">enabled</p>
          <p name="j">640ms</p>
          <p name="k">320ms</p>
          <p name="l">640ms</p>
          <p name="a">1280ms</p>
          <p name="l">6</p>
    </managedObject>
<managedObject class="New" distName="MB-85404/TB-85404/ST-4/c" version="xL20A_1911_002" operation="open">
          <p name="a">320ms</p>
          <p name="p">enabled</p>
          <p name="q">640ms</p>
          <p name="r">320ms</p>
          <p name="s">640ms</p>
          <p name="t">1280ms</p>
          <p name="u">6</p>
    </managedObject>'''

soup = BeautifulSoup('<data>' + xml_data + '</data>','xml')

r = re.compile(r'^MB-85404/TB-85404/ST-4/(?:a|b|c)')

for o in soup.find_all('managedObject',distName=r):
    o['distName'] = o['distName'].replace('85404','85409')
    p = o.find('p',{'name':'a'})
    p.string = 'UPDATED ' + p.string

soup.data.unwrap()
print(soup)

打印：

<?xml version="1.0" encoding="utf-8"?>
 <managedObject class="New" distName="MB-85409/TB-85409/ST-4/a" operation="open" version="xL20A_1911_002">
<p name="a">UPDATED 320ms</p>
<p name="b">enabled</p>
<p name="c">640ms</p>
<p name="d">320ms</p>
<p name="e">640ms</p>
<p name="f">1280ms</p>
<p name="g">6</p>
</managedObject>
<managedObject class="new" distName="AL-76867/MB-85404/TB-85404/ST-4/b" operation="open" version="xL20A_1911_002">
<p name="h">320ms</p>
<p name="i">enabled</p>
<p name="j">640ms</p>
<p name="k">320ms</p>
<p name="l">640ms</p>
<p name="a">1280ms</p>
<p name="l">6</p>
</managedObject>
<managedObject class="New" distName="MB-85409/TB-85409/ST-4/c" operation="open" version="xL20A_1911_002">
<p name="a">UPDATED 320ms</p>
<p name="p">enabled</p>
<p name="q">640ms</p>
<p name="r">320ms</p>
<p name="s">640ms</p>
<p name="t">1280ms</p>
<p name="u">6</p>
</managedObject>

编辑：要将每个85404中的85409更改为distName=，您可以这样做：

for o in soup.find_all('managedObject',{'distName': True}):
    o['distName'] = o['distName'].replace('85404','85409')

EDIT2：要替换整个文件，

with open("C:/files/abcd.xml","r") as f_in:
    xml_data = f_in.read()

with open("C:/files/output.xml","w") as f_out:
    f_out.write(xml_data.replace("85409","85904"))
beautifulsoupelementtreepython-3.xxmlxmlxmlxmlxmlxml