使用mutate和gsub将所有值替换为特定列中的NA

问题描述

在数据框中,我想将某些列中的所有值替换为NA。

Test2
       ID    Sex Location Obs1 Obs4        Obs5
1  291978 FEMALE        2 16.5 4836 0.563636364
2  292429 FEMALE        2 20.2 5428 0.584158416
3  292466 FEMALE        2 19.2   48 0.005208333
4  293656 FEMALE        2 15.8 2904 0.417721519
5  291993 FEMALE        2 18.1 6194 0.900552486
6  293263 FEMALE        2 17.9  616 0.078212291
7  290200 FEMALE        2 16.7  792 0.107784431
8  292511 FEMALE        2 18.3 4992 0.568306011
9  291510 FEMALE        2 18.6  350 0.037634409
10 293711 FEMALE        2 18.2  264 0.032967033
11 295234 FEMALE        2 16.5  216 0.036363636
12 293839 FEMALE        2 15.0 4114 0.806666667
13 291057 FEMALE        2 16.7   56 0.005988024
14 295094 FEMALE        2 16.5 3154 0.503030303
15 295562 FEMALE        2 14.7  966 0.142857143
16 292381 FEMALE        2 17.4 1980 0.258620690
17 289765 FEMALE        2 17.8 3492 0.544943820
18 293871 FEMALE        2 18.2 3760 0.516483516
19 291076 FEMALE        2 16.8   88 0.011904762
20 293851 FEMALE        2 16.1 2242 0.366459627

首先,我想指定应将哪些列的值替换为NA。只能是一列,也可以是多列。这就是为什么我更喜欢将其放入向量。

> Obs <- c('Obs1')

然后,我尝试使用以下方法将“ Obs1”列中的所有值替换为NA:

> deselect <- Test2 %>% mutate(across(paste(Obs),gsub(".*",NA,paste(Obs))))

但是,它给了我这个错误:

Error: Problem with `mutate()` input `..1`.
x Problem with `across()` input `.fns`.
i Input `.fns` must be NULL,a function,a formula,or a list of functions/formulas.
i Input `..1` is `across(paste(Obs),paste(Obs)))`.
Run `rlang::last_error()` to see where the error occurred.

有人知道如何在mutate内,mutate内使用gsub吗?还是应该使用其他方法?

非常感谢!

解决方法

或使用<!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF-8" /> <meta name="viewport" content="width=device-width,initial-scale=1.0" /> <!-- Bootstrap --> <link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.5.0/css/bootstrap.min.css" integrity="sha384-9aIt2nRpC12Uk9gS9baDl411NQApFmC26EwAOH8WgZl5MYYxFfc+NcPb1dKGj7Sk" crossorigin="anonymous" /> <title></title> </head> <body> <div class="container bg-color"> <div class="row pt-5"> <div class="col-12"> <input class="checkbox-tools test-tools" type="radio" name="typ-av-el" id="elhandel-button"> <label class="for-checkbox-tools" for="elhandel-button"> <p>button 1</p> </label> <!-- --> <input class="checkbox-tools test-tools" type="radio" name="typ-av-el" id="elnät-button"> <label class="for-checkbox-tools" for="elnät-button"> <p>button 2</p> </label> <div> </div> </div> <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script> <script src="https://stackpath.bootstrapcdn.com/bootstrap/4.5.0/js/bootstrap.min.js" integrity="sha384-OgVRvuATP1z7JjHLkuOU7Xw704+h835Lr+6QL9UvYjZE3Ipu6Tp75j7Bh/kR0JKI" crossorigin="anonymous"></script> </body> </html>

mutate_at
,

这就是您使用mutateacross的方式。

cols_na <- c("wt","hp")

mtcars %>% 
  mutate(across(one_of(cols_na),~ NA))
,

我建议使用一种base R方法,在Obs中定义要替换的列:

#Data
df <- structure(list(ID = c(291978L,292429L,292466L,293656L,291993L,293263L,290200L,292511L,291510L,293711L,295234L,293839L,291057L,295094L,295562L,292381L,289765L,293871L,291076L,293851L),Sex = c("FEMALE","FEMALE","FEMALE"),Location = c(2L,2L,2L),Obs1 = c(16.5,20.2,19.2,15.8,18.1,17.9,16.7,18.3,18.6,18.2,16.5,15,14.7,17.4,17.8,16.8,16.1),Obs4 = c(4836L,5428L,48L,2904L,6194L,616L,792L,4992L,350L,264L,216L,4114L,56L,3154L,966L,1980L,3492L,3760L,88L,2242L),Obs5 = c(0.563636364,0.584158416,0.005208333,0.417721519,0.900552486,0.078212291,0.107784431,0.568306011,0.037634409,0.032967033,0.036363636,0.806666667,0.005988024,0.503030303,0.142857143,0.25862069,0.54494382,0.516483516,0.011904762,0.366459627)),class = "data.frame",row.names = c("1","2","3","4","5","6","7","8","9","10","11","12","13","14","15","16","17","18","19","20"))

接下来的代码:

#Define cols
Obs <- c('Obs1')
#Assign
index <- which(names(df) %in% Obs) 
df[,index] <- gsub(".*",NA,df[,index])

输出:

       ID    Sex Location Obs1 Obs4        Obs5
1  291978 FEMALE        2 <NA> 4836 0.563636364
2  292429 FEMALE        2 <NA> 5428 0.584158416
3  292466 FEMALE        2 <NA>   48 0.005208333
4  293656 FEMALE        2 <NA> 2904 0.417721519
5  291993 FEMALE        2 <NA> 6194 0.900552486
6  293263 FEMALE        2 <NA>  616 0.078212291
7  290200 FEMALE        2 <NA>  792 0.107784431
8  292511 FEMALE        2 <NA> 4992 0.568306011
9  291510 FEMALE        2 <NA>  350 0.037634409
10 293711 FEMALE        2 <NA>  264 0.032967033
11 295234 FEMALE        2 <NA>  216 0.036363636
12 293839 FEMALE        2 <NA> 4114 0.806666667
13 291057 FEMALE        2 <NA>   56 0.005988024
14 295094 FEMALE        2 <NA> 3154 0.503030303
15 295562 FEMALE        2 <NA>  966 0.142857143
16 292381 FEMALE        2 <NA> 1980 0.258620690
17 289765 FEMALE        2 <NA> 3492 0.544943820
18 293871 FEMALE        2 <NA> 3760 0.516483516
19 291076 FEMALE        2 <NA>   88 0.011904762
20 293851 FEMALE        2 <NA> 2242 0.366459627

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