问题描述
我试图创建鱼眼效果,但只能在鼠标位置周围的小半径范围内。我已经能够修改this code来处理鼠标位置(demo),但是我无法弄清楚缩放的来源。我期望输出与此类似地扭曲图像(出于这个问题,忽略颜色反转):
相关代码:
// Check if within given radius of the mouse
vec2 diff = myUV - u_mouse - 0.5;
float distance = dot(diff,diff); // square of distance,saves a square-root
// Add fish-eye
if(distance <= u_radius_squared) {
vec2 xy = 2.0 * (myUV - u_mouse) - 1.0;
float d = length(xy * maxFactor);
float z = sqrt(1.0 - d * d);
float r = atan(d,z) / PI;
float phi = atan(xy.y,xy.x);
myUV.x = d * r * cos(phi) + 0.5 + u_mouse.x;
myUV.y = d * r * sin(phi) + 0.5 + u_mouse.y;
}
vec3 tex = texture2D(tMap,myUV).rgb;
gl_FragColor.rgb = tex;
这是我的第一个着色器,因此除了解决此问题外,还欢迎进行其他改进。
解决方法
计算从当前片段到鼠标的向量以及向量的长度:
vec2 diff = myUV - u_mouse;
float distance = length(diff);
新的纹理坐标是鼠标位置和缩放方向矢量的和:
myUV = u_mouse + normalize(diff) * u_radius * f(distance/u_radius);
例如:
uniform float u_radius;
uniform vec2 u_mouse;
void main()
{
vec2 diff = myUV - u_mouse;
float distance = length(diff);
if (distance <= u_radius)
{
float scale = (1.0 - cos(distance/u_radius * PI * 0.5));
myUV = u_mouse + normalize(diff) * u_radius * scale;
}
vec3 tex = texture2D(tMap,myUV).rgb;
gl_FragColor = vec4(tex,1.0);
}