问题描述
我是XSLT领域的初学者，所以在此先感谢您的理解。我有一个文件target.xml作为转换的主要输入，并且该文件包括订户：
<subscription-table>
<subscriber name="aries" useZipXfer="yes" usePubMed="no">
<ftp server="dummy.url1.com" port="21" remotedir="/XXXXXXX" userid="XXXXXXX" password="XXXXXXXXX" binary="yes" passive="no"/>
<notify-success>
<mail mailhost="smtprelayptc1.wkglobal.net" mailport="25" subject="MRCS-PS HEADER UPDATE - PAP">
<from address="success1.from@mail.com"/>
<to address="success1.to@mail.com"/>
</mail>
</notify-success>
<notify-failure>
<mail mailhost="smtprelayptc1.wkglobal.net" mailport="25" subject="MRCS-PS HEADER UPDATE - PAP">
<from address="failure1.from@mail.com"/>
<to address="failure1.to@mail.com"/>
</mail>
</notify-failure>
</subscriber>
<subscriber name="cas" useZipXfer="no" usePubMed="yes" sendPromote="no">
<ftp server="dummy.url2.com" port="21" remotedir="/YYYYYYY" userid="YYYYYYY" password="YYYYYYYYY" binary="yes" passive="no"/>
<notify-success>
<mail mailhost="smtprelayptc1.wkglobal.net" mailport="25" subject="MRCS-PS HEADER UPDATE - PAP">
<from address="success2.from@mail.com"/>
<to address="success2.to@mail.com"/>
</mail>
</notify-success>
<notify-failure>
<mail mailhost="smtprelayptc1.wkglobal.net" mailport="25" subject="MRCS-PS HEADER UPDATE - PAP">
<from address="failure2.from@mail.com"/>
<to address="failure2.to@mail.com"/>
</mail>
</notify-failure>
</subscriber>
</subscription-table>
对于target.xml文件中的每个订户，我都有一个单独的文档，其中包含订户名称。例如，我有aries_subscriptions.xml，cas_subscriptions.xml。在每个订阅文件中，我都有日记数据。例如，在aries_subscriptions.xml中，我具有：
<subscription>
<database status="update" name="ovftdb">
<journal status="*" name="00002030" >
<issue status="new" pubdate="01/01/2004" name="*" an="99999999-999999999-99999" >
<header/>
</issue>
</journal>
<journal status="*" name="00000374" >
<issue status="new" pubdate="01/01/2004" name="*" an="99999999-999999999-99999" >
<header/>
</issue>
</journal>
<journal status="*" name="00000372" >
<issue status="new" pubdate="01/01/2004" name="*" an="99999999-999999999-99999" >
<header/>
</issue>
</journal>
...
我需要使用target.xml作为转换的输入，并为每个订阅者打开其文件，找到其日志，并获取其名称和发布日期属性。例如，对于“ aries”订户，我需要打开aries_subscriptions.xml，并获取日记名称和发布日期。最后，对于所有订阅者，我需要生成lookup.xml文件：
<journals xmlns:xlink="http://www.w3.org/1999/xlink">
<journal name="12345678">
<target identifier="aries" pubdate="01/01/2006">
<targetLink xmlns:xlink="http://www.w3.org/1999/xlink" xlink:href="targets.xml#xpointer(/descendant::subscriber[attribute::name='subscriberId1'])"/>
</target>
<target identifier="subscriberId2" pubdate="01/01/2006">
<targetLink xmlns:xlink="http://www.w3.org/1999/xlink" xlink:href="targets.xml#xpointer(/descendant::subscriber[attribute::name='subscriberId2'])"/>
</target>
</journal>
<journal name="23456781">
<target identifier="cas" pubdate="01/01/2006">
<targetLink xmlns:xlink="http://www.w3.org/1999/xlink" xlink:href="targets.xml#xpointer(/descendant::subscriber[attribute::name='subscriberId2'])"/>
</target>
<target identifier="subscriberId2" pubdate="01/01/2006">
<targetLink xmlns:xlink="http://www.w3.org/1999/xlink" xlink:href="targets.xml#xpointer(/descendant::subscriber[attribute::name='subscriberId3'])"/>
</target>
</journal>
</journals>
我的xslt是：
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:xlink="http://www.w3.org/1999/xlink"
xmlns:saxon="http://saxon.sf.net/"
exclude-result-prefixes="xs xsl saxon xlink">
<xsl:strip-space elements="*" />
<xsl:output method="xml" omit-xml-declaration="no"
indent="yes" encoding="UTF-8" saxon:character-representation="entity" />
<xsl:include href="utilities.xsl" />
<xsl:variable name="inputFolderAndFile">
<xsl:call-template
name="getValuesBeforeAndAfterLastOccurance">
<xsl:with-param name="inputString"
select="string(base-uri(.))" />
<xsl:with-param name="char" select="'/'" />
</xsl:call-template>
</xsl:variable>
<xsl:variable name="inputFolderPath"
select="substring-before($inputFolderAndFile,'*')" />
<xsl:variable name="inputFile"
select="substring-after($inputFolderAndFile,'*')" />
<xsl:variable name="tokens"
select="tokenize($inputFile,'\.')" />
<xsl:variable name="baseFileName"
select="string-join($tokens[not(.=$tokens[last()])],'.')" />
<xsl:template match="@* | * | comment() | processing-instruction()">
<xsl:apply-templates select="@* | node()" />
</xsl:template>
<xsl:template match="text()">
<xsl:copy/>
</xsl:template>
<!-- <xsl:template match="text()" mode="journal-processing"/> -->
<xsl:template match="subscriber">
<xsl:variable name="subscriberName" select="document(concat($inputFolderPath,'/',@name,'_subscriptions.xml'))" />
<xsl:value-of select="$subscriberName" />
<xsl:apply-templates mode="journal-processing"/>
</xsl:template>
<xsl:template match="journal" mode="journal-processing">
<xsl:variable name="journalName" select="@name" />
<xsl:variable name="journalPubDate" select="issue/@pubdate" />
<xsl:variable name="subscriberNameFromDoc" select="substring-before('.','_subscriptions')" />
<xsl:element name="journal">
<xsl:attribute name="name" select="$journalName"/>
<xsl:element name="target">
<xsl:attribute name="identifier" select="$subscriberNameFromDoc"/>
<xsl:attribute name="pubdate" select="$journalPubDate"/>
<xsl:element name="targetLink">
<xsl:attribute name="xlink">http://www.w3.org/1999/xlink</xsl:attribute>
<xsl:attribute name="xlink:href">$baseFileName#xpointer(/descendant::subscriber[attribute::name='$subscriberName'])</xsl:attribute>
</xsl:element>
</xsl:element>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
但是，不幸的是，结果是我只有空的xml文档。您能帮我解决这个问题吗？预先感谢您的帮助。
解决方法
当我应用Martin的注释时，我的代码起作用了。因此，请看一下解决方案：
<xsl:template match="subscriber">
<xsl:variable name="subscriberName" select="document(concat($inputFolderPath,'/',@name,'_subscriptions.xml'))" />
<xsl:apply-templates select="$subscriberName" mode="journal-processing"/>
</xsl:template>