将具有相同 ItemNumber 的节点合并为一行

问题描述

某些供应商定期发布带有商品价格的 XML 文件。文件中有两种价格：目录价格（list Price）和折扣价格（discount Price）

<prices>
<price>
    <itemNumber>100</itemNumber>
    <currency>PLN</currency>
    <amount>2.98</amount>
    <type>listPrice</type>
</price>
<price>
    <itemNumber>100</itemNumber>
    <currency>PLN</currency>
    <amount>1.19</amount>
    <type>discountPrice</type>
</price>
<price>
    <itemNumber>101</itemNumber>
    <currency>PLN</currency>
    <amount>3.88</amount>
    <type>listPrice</type>
</price>
<price>
    <itemNumber>101</itemNumber>
    <currency>PLN</currency>
    <amount>2.76</amount>
    <type>discountPrice</type>
</price>
<price>
    <itemNumber>102</itemNumber>
    <currency>PLN</currency>
    <amount>4.55</amount>
    <type>listPrice</type>
</price>
<price>
    <itemNumber>102</itemNumber>
    <currency>PLN</currency>
    <amount>3.20</amount>
    <type>discountPrice</type>
</price>
<price>
    <itemNumber>103</itemNumber>
    <currency>PLN</currency>
    <amount>3.38</amount>
    <type>listPrice</type>
</price>
<price>
    <itemNumber>103</itemNumber>
    <currency>PLN</currency>
    <amount>2.90</amount>
    <type>discountPrice</type>
</price>
<price>
    <itemNumber>104</itemNumber>
    <currency>PLN</currency>
    <amount>2.98</amount>
    <type>listPrice</type>
</price>
<price>
    <itemNumber>104</itemNumber>
    <currency>PLN</currency>
    <amount>1.19</amount>
    <type>discountPrice</type>
</price>
</prices>

目前我正在将 XML 文件上传到数据库，然后我正在使用从 xml 表中获取的数据创建 tmp 表。

SELECT
@supplierID     AS supplierID,a.product.query('itemNumber').value('.','varchar(50)')   AS supplierCode,a.product.query('amount').value('.','MONEY') AS PricePLN,a.product.query('type').value('.','varchar(50)') AS NetPriceTypePLN,GETDATE()         AS CreateDate
INTO Prices_tmp
FROM ImportedXML x(nolock)
OUTER APPLY x.xmlData.nodes('prices/price') as a(product)
where 
x.Fileid = 111

我正在努力解决的问题是如何读取 XML 以在一行中获取两个价格 喜欢：

ItemNumber | ListedPriceAmount | discountPriceAmount
100        | 2.98              | 1.19
101        | 3.88              | 2.76
102        | 4.55              | 3.20
103        | 3.38              | 2.90

你能帮我吗？我花了很多时间自己尝试。

解决方法

请尝试以下解决方案。

要点：

• 将适当的 XML 分解为关系/矩形格式。
• 简单模拟 PIVOT 操作以实现所需 输出。

SQL

DECLARE @xml XML = 
N'<prices>
    <price>
        <itemNumber>100</itemNumber>
        <currency>PLN</currency>
        <amount>2.98</amount>
        <type>listPrice</type>
    </price>
    <price>
        <itemNumber>100</itemNumber>
        <currency>PLN</currency>
        <amount>1.19</amount>
        <type>discountPrice</type>
    </price>
    <price>
        <itemNumber>101</itemNumber>
        <currency>PLN</currency>
        <amount>3.88</amount>
        <type>listPrice</type>
    </price>
    <price>
        <itemNumber>101</itemNumber>
        <currency>PLN</currency>
        <amount>2.76</amount>
        <type>discountPrice</type>
    </price>
    <price>
        <itemNumber>102</itemNumber>
        <currency>PLN</currency>
        <amount>4.55</amount>
        <type>listPrice</type>
    </price>
    <price>
        <itemNumber>102</itemNumber>
        <currency>PLN</currency>
        <amount>3.20</amount>
        <type>discountPrice</type>
    </price>
    <price>
        <itemNumber>103</itemNumber>
        <currency>PLN</currency>
        <amount>3.38</amount>
        <type>listPrice</type>
    </price>
    <price>
        <itemNumber>103</itemNumber>
        <currency>PLN</currency>
        <amount>2.90</amount>
        <type>discountPrice</type>
    </price>
    <price>
        <itemNumber>104</itemNumber>
        <currency>PLN</currency>
        <amount>2.98</amount>
        <type>listPrice</type>
    </price>
    <price>
        <itemNumber>104</itemNumber>
        <currency>PLN</currency>
        <amount>1.19</amount>
        <type>discountPrice</type>
    </price>
</prices>';

WITH rs AS
(
    SELECT c.value('(itemNumber/text())[1]','varchar(50)') AS ItemNumber,c.value('(amount/text())[1]','money') AS amount,c.value('(type/text())[1]','varchar(50)') AS type 
    FROM @xml.nodes('/prices/price') AS t(c)
)
-- simulates PIVOT operation
SELECT DISTINCT
    ItemNumber,MAX(IIF(type = 'listPrice',amount,0)) OVER (PARTITION BY ItemNumber) AS ListedPriceAmount,MAX(IIF(type = 'discountPrice',0)) OVER (PARTITION BY ItemNumber) AS discountPriceAmount
FROM rs;

输出

+------------+-------------------+---------------------+
| ItemNumber | ListedPriceAmount | discountPriceAmount |
+------------+-------------------+---------------------+
|        100 |              2.98 |                1.19 |
|        101 |              3.88 |                2.76 |
|        102 |              4.55 |                3.20 |
|        103 |              3.38 |                2.90 |
|        104 |              2.98 |                1.19 |
+------------+-------------------+---------------------+

,

如果pivot操作太难记了，试试这个方法：

DECLARE @xml XML = '...'

WITH rs AS
(
    SELECT c.value('(itemNumber/text())[1]','varchar(50)') AS type 
    FROM @xml.nodes('/prices/price') AS t(c)
),sr as
(
    SELECT
            ItemNumber,amount ListedPriceAmount,0 discountPriceAmount 
    FROM rs
    where type = 'listPrice'
    union
    SELECT
            ItemNumber,0 ListedPriceAmount,amount discountPriceAmount 
    FROM rs
    where type = 'discountPrice'
)
select ItemNumber,sum(ListedPriceAmount) ListedPriceAmount,sum(discountPriceAmount) discountPriceAmount
from sr
group by ItemNumber

结果与 Yitzhak 的回答相同。