ADO中SQL Server 2008的日期时间的等效数据类型是什么?

问题描述

| sql Server 2008中的datetime数据类型支持毫秒。 我正在尝试执行一个接受datetime参数的存储过程,该参数带有一个以毫秒为单位的arg作为输入/输出值。 我无法将传递给方法字符串转换为datetime值。当我不传递毫秒值时,转换将正确进行。 我在以下方法中看到转换问题。
Set objpara2 = objCom.CreateParameter(\"datetime\",adDate,adParamInputOutput,\"2011-01-01 11:01:01.123\")
ADO中sql Server 2008的日期时间的等效数据类型是什么? 这是完整的代码片段:
CREATE PROCEDURE [dbo].[TestProc] @time1 time,@datetime datetime output
as
begin
    SET NOCOUNT ON;
    select @datetime = datetime from ALLTimeTypes where time = @time1;
end

Private Sub Command1_Click()
    Dim objCon As ADODB.connection
    Dim objCom As ADODB.command
    Dim objPara As ADODB.Parameter
    Dim objpara2 As ADODB.Parameter
    Dim objRS As ADODB.Recordset
    Dim k As Integer

    Set objCon = New ADODB.connection
    Set objCom = New ADODB.command

    objConConnectionString = \"Provider=sqlNCLI10;\" _
         & \"Data Source=ES-89W87BS;\" _
         & \"Database=MASTER;\" _
         & \"Integrated Security=sspI;\" _
         & \"DataTypeCompatibility=80;\" _
         & \"User ID=sa;\" _
         & \"Password=<redacted>;\"

    objCon.ConnectionString = objConConnectionString
    objCon.Open        
    MsgBox \"Connection opened\"

    With objCom
        .CommandText = \"TestProc\"     \'Name of the stored procedure
        .CommandType = adCmdstoredProc  \'Type : stored procedure
        .ActiveConnection = objCon.ConnectionString
    End With

    Set objPara = objCom.CreateParameter(\"time1\",adVarChar,adParamInput,50,\"02:02:02.3456123\")
    Set objpara2 = objCom.CreateParameter(\"datetime\",\"2011-01-01 11:01:01\")

    objCom.Parameters.Append objPara
    objCom.Parameters.Append objpara2

    Set objRS = objCom.Execute        
    objRS.Open
    do while Not objRS.EOF
        For k = 0 To objRS.Fields.Count - 1
            Debug.Print objRS(k).Name & \": \" & objRS(k).Value
        Next
        objRS.MoveNext
    Loop        
    ...
    

解决方法

据此,
adDBTimeStamp
    ,显然ADO删除了毫秒。 http://support.microsoft.com/kb/246438 我还没有尝试过,但是我认为您应该将存储过程中参数的数据类型更改为varchar(23),并使用一个类似于“ 3”的字符串参数。     ,如果在日期和时间部分之间的字符串值中包含“ 4”,会发生什么情况? (例如
2011-01-01T11:01:01.123
Set objpara2 = objCom.CreateParameter(\"datetime\",adDate,adParamInputOutput,\"2011-01-01T11:01:01.123\")