问题描述
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我在寻找可以处理网站缩略图的传呼机,但没有找到任何内容,因此必须自己编写。我写了一个函数,可以根据AJAX请求对任何数据进行寻呼:
function addPager(s,m,f,pager,current) {
if (!current) {current = 2;}
// m - element / page
// s - all elements
// f - ajax getter function\'s name like functionName(id,page)
// current - pressed button\'s index or p n f l as prev next first last
if (!pager) { // if the pager not appended
if (s%m == 0) { p = s/m; } else {p = parseInt(s/m);} // get the pages number on all elements / elementsonpage
$pager = $(\'<div class=\"pager clearfix\"></div>\') // pager holder Box
for (i=0;i<=p;i++) // append all pages to the pager holder and bind them for click
{
$(\'<span>\'+(i+1)+\'</span>\')
.bind(\"click\",{page: i},f)
.click(function(){
var ind = $(this).index();
addPager(s,$(this).parent(\"div\"),ind); // on click call this function again
})
.appendTo($pager); // the append
}
$pager.find(\"span\").eq(0).addClass(\"on\"); // find first element and add on class because its just appended
$(\'<span class=\"mod\">Next</span>\').click(function(){ addPager(s,\"n\"); }).appendTo($pager); // prev,next,first,last buttons
$(\'<span class=\"mod\">Prev</span>\').click(function(){ addPager(s,\"p\"); }).prependTo($pager);
$(\'<span class=\"mod\">Last</span>\').click(function(){ addPager(s,\"l\"); }).appendTo($pager);
$(\'<span class=\"mod\">First</span>\').click(function(){ addPager(s,\"f\"); }).prependTo($pager);
$pager.children(\"span\").eq(0).addClass(\"on\"); // add on class for the Now 1st element (which is the first button)
$pager.children(\"span\").eq(1).addClass(\"disabled\"); // disable the prev button
$pager.children(\"span:not(.mod)\").each(function(index) {
if (((current-3) > (index+2)) || ((current+3) < (index+2))) { $(this).hide(); } else { $(this).show(); } // hide everything but the first 6 buttons (in case of 1000 pages i just show 1 .. 6)
if (current == (index+2)) { $(this).addClass(\"on\"); } // add on class to the first element - its probably useless because of the prevIoUs addonclass
});
return($pager); // return it for the function which called. i append in the primary ajax function.
}
else { // if the pager is already appended to the site
if (s%m == 0) { p = s/m; } // calculate pages
else {p = parseInt(s/m);} // calculate pages
if (current == \"n\") {var i = $pager.find(\"span:not(.mod).on\").index(); if ((i>=1) && (i<(p+2))) {addPager(s,(i+1));}} // if current next goto next
else if (current == \"p\") {var i = $pager.find(\"span:not(.mod).on\").index(); if ((i>2) && (i<=(p+2))) {addPager(s,(i-1));}} // if current prev goto prev
else if (current == \"f\") { addPager(s,2); } // 1st
else if (current == \"l\") { addPager(s,(p+2)); } // last
else { // if any other button pressed
$pager = pager;
$pager.find(\"span\").removeClass(\"on disabled\"); // remove on or disabled classes on each buttons
$pager.find(\"span:not(.mod)\").each(function(index) { // find numbered items only (without the spec buttons like prev or last)
if (((current-3) > (index+2)) || ((current+3) < (index+2))) { $(this).hide(); } else { $(this).show(); } // hide all the buttons but the nearest ones
if (current == (index+2)) { $(this).addClass(\"on\"); }
});
if (current == 2) { $pager.children(\"span\").eq(0).addClass(\"on\"); $pager.children(\"span\").eq(1).addClass(\"disabled\"); }// first button makes the prev diabled and first active
if (current == (p+2)) { $pager.children(\"span\").eq(p+4).addClass(\"on\"); $pager.children(\"span\").eq(p+3).addClass(\"disabled\"); } // last button makes the next diabled and last active
}
}
}
...可以这样使用;
$.ajax {
...
addPager(allelementsnumber,elementsonpage,thisajaxfunctionsname);
$pager.appendTo(whereyouwanttoappendthis);
...
}
CC许可,如果需要,可以使用它,它可以正常工作:)
当我多次调用addPager(param,param,param)
时,它具有如此多的参数...它会占用大量内存还是类似的东西?
如何使该功能更好或更快速?
为了便于理解,我发表了一些评论,但是我认为这不是一个复杂的功能。
解决方法
最好创建一个带有属性的对象,然后传递该对象而不是多个参数。对象的每个属性将代表一个参数。您可以将其视为选项/配置对象。
然后,您可以将对象作为单个参数传递给函数,然后使用对象的属性。
这是一种更好的方法,因为从长远来看,它提供了更好的可伸缩性。
但是,我不确定使用许多参数会产生开销。在我看来,它只是很难阅读且扩展性不强。