如果不存在xml节点，则使用simpleXML创建它？

问题描述

| 如果不存在xml节点，则使用simpleXML创建它？ 当我print_r（）我的xml时输出

Array
 (
[0] => SimpleXMLElement Object
    (
        [A] => SimpleXMLElement Object
            (
                [a] => a
            )

        [B] => SimpleXMLElement Object
            (
                [b] => b
            )

        [C] => SimpleXMLElement Object
            (
                [c] => SimpleXMLElement Object
                    (
                        [c1] => c1
                    )

            )

        [D] => SimpleXMLElement Object
            (
                [d] => d
            )

        [E] => SimpleXMLElement Object
            (
                [e] => SimpleXMLElement Object
                    (
                        [e1] => e1
                    )

            )

    )
 [1] => SimpleXMLElement Object
    (
        [A] => SimpleXMLElement Object
            (
                [a] => a11
            )

        [B] => SimpleXMLElement Object
            (
                [b] => b11
            )

        [C] => SimpleXMLElement Object
            (
                [c] => SimpleXMLElement Object
                    (
                        [c1] => c11
                    )

            )

        [D] => SimpleXMLElement Object
            (
                [d] => d1
            )

        [E] => SimpleXMLElement Object
            (
                [e] => SimpleXMLElement Object
                    (
                        [e1] => e11
                    )

            )

    )

） 我要检查

( node <F><f1>f1<f1></F> )

[F] => SimpleXMLElement Object(
          [f1] => f1
 )

如果不存在，则创建此节点 ANYBODY可以给出方法如何使用simpleXML做到这一点？     

解决方法

        这很容易：

$xml = \'<xml></xml>\';
$sxml = new SimpleXMLElement($xml);

if (!isset($sxml->F->f1)) {
   $sxml->addChild(\'F\')->addChild(\'f1\',\'f1\');
}

echo $sxml->asXML();

你得到：

<?xml version=\"1.0\"?>
<xml><F><f1>f1</f1></F></xml>