xml – 如何将此文件转换为yml?

如何将此文件转换为yml?

<container xmlns="http://symfony.com/schema/dic/services"
        xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
        xsi:schemaLocation="http://symfony.com/schema/dic/services http://symfony.com/schema/dic/services/services-1.0.xsd">
        <services>
           <service id="sonata.admin.course" class="YourNS\AdminBundle\Admin\BlogAdmin">
              <tag name="sonata.admin" manager_type="orm" group="Posts" label="Blog"/>
              <argument />
              <argument>YourNS\AdminBundle\Entity\Course</argument>
              <argument>SonataAdminBundle:CRUD</argument>
              <call method="setTranslationDomain">
                  <argument>YourNSAdminBundle</argument>
              </call>
          </service>
       </services>
    </container>

解决方法

像这样的东西(我没试过):

services:
  sonata.admin.course:
    class: YourNS\AdminBundle\Admin\BlogAdmin
    arguments: [null,YourNS\AdminBundle\Entity\Course,'SonataAdminBundle:CRUD']
    calls:
        - [setTranslationDomain,YourNSAdminBundle]
    tags:
        - { name: sonata.admin,manager_type: orm,group: Posts,label: Blog }

相关文章

php输出xml格式字符串
J2ME Mobile 3D入门教程系列文章之一
XML轻松学习手册
XML入门的常见问题(一)
XML入门的常见问题(三)
XML轻松学习手册(2)XML概念