<Foo>
<Name>Some Data</Name>
<Bar_Data>Other Data</Bar_Data>
<Bar_MoreData>More Data</Bar_MoreData>
</Foo>
我想把它变成一个看起来像这样的C#类
public class Foo
{
public string Name {get; set; }
public Bar Bar { get; set; }
}
public class Bar
{
public string Data { get; set; }
public string MoreData { get; set; }
}
有什么方法可以仅通过简单的数据注释(XmlRoot,XmlElement等)来完成此操作,还是我实现IXmlSerializable的唯一选择?
编辑:注意,我只需要反序列化数据.我从第三方获得XML,并且不需要将Foo序列化回XML(如果这样更容易).
解决方法:
一种选择是使用XmlAnyElementAttribute,如下所示:
public class Foo
{
public string Name { get; set; }
public Bar Bar { get; set; }
[XmlAnyElementAttribute]
public XmlElement[] BarElements
{
get { return null; }
set
{
Bar = new Bar();
var barType = Bar.GetType();
foreach (var prop in value)
barType.GetProperty(prop.Name.Substring(4)).SetValue(Bar, prop.InnerText);
}
}
}
public class Bar
{
public string Data { get; set; }
public string MoreData { get; set; }
}
当XmlSerializer无法识别元素时,它将其添加到XmlAnyElementAttribute标记的XmlElement []类型的属性中.在这里可以处理钢筋属性.我在那里使用反射来展示这个想法.
另一个选择是反序列化两次并将Bar与Foo连接:
public class Foo
{
public string Name { get; set; }
public Bar Bar { get; set; }
}
[XmlRoot("Foo")]
public class Bar
{
[XmlElement("Bar_Data")]
public string Data { get; set; }
[XmlElement("Bar_MoreData")]
public string MoreData { get; set; }
}
var foo = (Foo) new XmlSerializer(typeof (Foo)).Deserialize(...);
var bar = (Bar) new XmlSerializer(typeof (Bar)).Deserialize(...);
foo.Bar = bar
不会干扰反序列化的另一种选择:
public class Foo
{
public string Name { get; set; }
public Bar Bar { get; set; }
}
public class Bar
{
public string Data { get; set; }
public string MoreData { get; set; }
}
var fooSerializer = new XmlSerializer(typeof (Foo));
fooSerializer.UnkNownElement += (sender, e) =>
{
var foo = (Foo) e.ObjectBeingDeserialized;
if(foo.Bar == null)
foo.Bar = new Bar();
var propName = e.Element.Name.Substring(4);
typeof(Bar).GetProperty(propName).SetValue(foo.Bar, e.Element.InnerText);
};
var fooInstance = fooSerializer.Deserialize(...);
如果双重反序列化或反射是有问题的性能明智的选择,则可以创建代理代理类:
[XmlRoot("Foo")]
public class FooSurrogate
{
public string Name { get; set; }
public string Bar_Data { get; set; }
public string Bar_MoreData { get; set; }
public Foo ToFoo()
{
return new Foo
{
Name = Name,
Bar = new Bar
{
Data = Bar_Data,
MoreData = Bar_MoreData
}
};
}
}
var seializer = new XmlSerializer(typeof (FooSurrogate));
var foo = ((FooSurrogate) seializer.Deserialize(...)).ToFoo();