用JAXB从对象生成XML

Java代码

1. importjava.io.FileOutputStream;
3. importjavax.xml.bind.JAXBContext;
4. importjavax.xml.bind.Marshaller;
5. importjavax.xml.bind.annotation.XmlRootElement;
6. publicclassJavaToXMLDemo{
7. staticvoidmain(String[]args)throwsException{
8. JAXBContextcontext=JAXBContext.newInstance(Employee.class);
9. Marshallerm=context.createMarshaller();
10. m.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT,true);
11. Employeeobject=newEmployee();
12. object.setCode("CA");
13. object.setName("Cath");
14. object.setSalary(300);
15. m.marshal(object,System.out);
16. }
17. }

@XmlRootElement

classEmployee{

privateStringcode;

privateStringname;

privateintsalary;

publicStringgetCode(){

returncode;

voidsetCode(Stringcode){

this.code=code;

publicStringgetName(){

returnname;

voidsetName(Stringname){

this.name=name;

intgetSalary(){

returnsalary;

voidsetSalary(intpopulation){

this.salary=population;

运行结果:

Xml代码

<?xmlversion="1.0"encoding="UTF-8"standalone="yes"?>
1. <employee>
2. code>CA</name>Cathsalary>300>