发送xml数据给服务器

http://www.cnblogs.com/linjiqin/archive/2011/06/02/2069621.html

一、发送xml数据

public static void main(String[] args) throws Exception {
        String xml = "<?xml version=\"1.0\" encoding=\"UTF-8\"?><videos><video><title>中国</title></video></videos>";
        String path =  http://localhost:8083/videoweb/video/manage.do?method=getXML ;
        
        byte[] entity = xml.getBytes("UTF-8");
        HttpURLConnection conn = (HttpURLConnection) new URL(path).openConnection();
        conn.setConnectTimeout(5000);
        conn.setRequestMethod("POST");
        conn.setDoOutput(true);        //指定发送的内容类型为xml
        conn.setRequestProperty("Content-Type","text/xml; charset=UTF-8");
        conn.setRequestProperty("Content-Length",String.valueOf(entity.length));
        OutputStream outStream = conn.getoutputStream();
        outStream.write(entity);
        if(conn.getResponseCode() == 200){
            System.out.println("发送成功");
        }else{
            System.out.println("发送失败");
        }
    }

二、接受xml数据

public ActionForward getXML(ActionMapping mapping,ActionForm form,HttpServletRequest request,HttpServletResponse response)
            throws Exception {
        InputStream inStream = request.getInputStream();
        byte[] data = StreamTool.read(inStream);
        String xml = new String(data,"UTF-8");
        System.out.println(xml);
        return mapping.findForward("result");
    }