在这里,我正在创建一个模拟猜谜游戏的简单练习
Windows手机应用程序.我有一个运行游戏的while循环,直到用户猜出正确的答案;我想要做的是在每个循环的开始,等待用户通过在文本框中按Enter键来触发事件.我是这个想法的新手,没有多线程经验.
我正在接受未经授权的访问,我不确定是什么导致它.
我正在接受未经授权的访问,我不确定是什么导致它.
public partial class MainPage : PhoneApplicationPage { Random r; int guess; static AutoResetEvent autoEvent; // Constructor public MainPage() { InitializeComponent(); r = new Random(); autoEvent = new AutoResetEvent(false); Thread t = new Thread(PlayGuessGame); t.Start(); } private void PlayGuessGame() { bool hasWon = false; int secretNumber = r.Next(1,3); int tries = 1; messageTextBox.Text = "Guess a number"; while (!hasWon) { autoEvent.WaitOne(); if (guess == secretNumber) //if user wins { messageTextBox.Text = "Congratulations! You've guess the correct number! It took {0} tries."; } else { tries++; if (guess < secretNumber) messageTextBox.Text = "Guess higher!"; else messageTextBox.Text = "Guess lower!"; lastGuessTextBox.Text = guess.ToString(); } } } private void guessTextBox_KeyDown(object sender,KeyEventArgs e) { if (e.Key == Key.Enter) { guess = int.Parse(guessTextBox.Text); autoEvent.Set(); } } }
解决方法
您遇到的问题是因为您尝试从未创建的线程访问对象.因此,运行PlayGuessGame()的线程不应该在该沙箱中播放.你可以通过使用MethodInvoder解决这个问题:
private void PlayGuessGame() { bool hasWon = false; int secretNumber = r.Next(1,3); int tries = 1; messageTextBox.Text = "Guess a number"; while (!hasWon) { autoEvent.WaitOne(); if (guess == secretNumber) //if user wins { this.Invoke(new MethodInvoker(delegate { messageTextBox.Text = "Congratulations! You've guess the correct number! It took {0} tries."; })); } else { tries++; if (guess < secretNumber) this.Invoke(new MethodInvoker(delegate { messageTextBox.Text = "Guess higher!"; })); else this.Invoke(new MethodInvoker(delegate { messageTextBox.Text = "Guess lower!"; })); this.Invoke(new MethodInvoker(delegate { lastGuessTextBox.Text = guess.ToString(); })); } } }
我肯定会推荐Brian Warshaw的评论,这应该是一个事件驱动的GUI.希望这有帮助,你可以在其他地方使用你使用线程!