Jquery Ajax学习实例 向页面发出请求,返回XML格式数据

一、AjaxSample.aspx

处理业务数据,产生XML数据,供JqueryRequest.aspx调用代码如下:

protected void Page_Load(object sender,EventArgs e)
{
string uid = Request.QueryString["username"];
string pwd = Request.QueryString["password"];

Response.ContentType = "application/xml";
Response.Charset = "utf-8";

Response.Write("<?xml version='1.0' encoding='utf-8'?>");
Response.Write(@"<comments>");
Response.Write(@"<comment username='" + uid + "' password='" + pwd + "'>");
Response.Write(@"<content>上海市 徐汇区</content>");
Response.Write(@"</comment>");
Response.Write(@"</comments>");

Response.End();
}

二、JqueryRequest.aspx

通过点击按钮来请求AjaxSample.aspx,获取XMl数据。代码如下:



<html xmlns="http://www.w3.org/1999/xhtml">
<head runat="server">
<title></title>
<script type="text/javascript" src="js/jquery-1.3.2.js"></script>
</head>
<body>
<form id="form1" runat="server">
<div id="fdiv">
<input type="text" id="Text1"/><br />
<input type="text" id="Text2"/><br />
</div>
<div>
<div id="result">div1div1div1</div>
<input type="button" onclick="btnClick()" />
</div>
<div>
<script type="text/javascript">
// $(document).ready(
function btnClick() {
var uid = $("#Text1").val();
var pwd = $("#Text2").val();
$.ajax({
url: "AjaxSample.aspx",
type: "Get",
datatype: "xml",
data: { username: uid,password: pwd },
success: function(data,status) {
var u = $(data).find("comment").attr("username");
var p = $(data).find("comment").attr("password");
var a = $(data).find("comment content").text();
var info = "用户:" + u + " 密码:" + p + "的住址是:" + a;
$("#result").html(info);
}
});
}//);
</script>
</div>
</form>
</body>
</html>

相关文章

问题背景 最近小伙伴提了一个希望提高后台下拉列表可操作性的...
// n位随机数生成 function randomNum(n) { let sString = &...
HTML是HyperText Markup Language的简称,中文名称:超文本标...
层叠样式表(英文全称:Cascading Style Sheets)是一种用来表现...
JavaScript 是脚本语言,是一种解释性脚本语言(代码不进行预...
本文由葡萄城技术团队原创并首发 转载请注明出处:葡萄城官网...