javascript – mocha done()和async await的矛盾问题

我有以下测试用例：

it("should pass the test", async function (done) {
        await asyncFunction();
        true.should.eq(true);
        done();
    });

运行它断言：

Error: Resolution method is overspecified. Specify a callback or
return a Promise; not both.

如果我删除done();声明,它声称：

Error: Timeout of 2000ms exceeded. For async tests and hooks, ensure
“done()” is called; if returning a Promise, ensure it resolves.

如何解决这个悖论？

解决方法:

您还需要删除done参数,而不仅仅是对它的调用.像Mocha这样的测试框架会查看函数的参数列表(或至少它的arity),以了解您是使用完成还是类似.

使用Mocha 3.5.3,这适用于我(必须将true.should.be(true)更改为assert.ok(true),因为前者抛出错误)：

const assert = require('assert');

function asyncFunction() {
    return new Promise(resolve => {
        setTimeout(resolve, 10);
    });
}

describe('Container', function() {
  describe('Foo', function() {
    it("should pass the test", async function () {
        await asyncFunction();
        assert.ok(true);
    });
  });
});

但如果我添加完成：

describe('Container', function() {
  describe('Foo', function() {
    it("should pass the test", async function (done) {  // <==== Here
        await asyncFunction();
        assert.ok(true);
    });
  });
});

……然后我明白了

Error: Timeout of 2000ms exceeded. For async tests and hooks, ensure “done()” is called; if returning a Promise, ensure it resolves.