彩色文本输出

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#!/bin/bash

#输出彩色文字，需要四个参数,分别是前景色，背景色，样式，文字
function ColorText()
{
#判断参数个数，更加严格的判断比如是否超过范围这里就不做详细判断了
        if [ $# -ne 4  ]
        then
                echo "Usage:4 parameters are needed!"
                echo "ForeColor,BackgroundClor Style and Text!"
                ShowHelp;
        else
                Fg="3""$1"
                Bg="4""$2"
                SetColor="\E[""$Fg;$Bg""m"
                Style="\033[""$3""m"
                Text="$4"
                EndStyle="\033[0m"
                echo -e "$SetColor""$Style""$Text""$EndStyle"
        fi;
}

#输出帮助信息
function ShowHelp()
{
        echo "The frst parameter is a number ranged from 1 to 10,represents the foreground color."
        echo "The second parameter is  a number ranged from 1 to 10,represents the background color."
        ColorText 1 8 2 "1    red";
        ColorText 2 8 2 "2    green";
        ColorText 3 8 2 "3    yellow";
        ColorText 4 8 2 "4    blue";
        ColorText 5 8 2 "5    magenta";
        ColorText 6 8 2 "6    cyan";
        ColorText 7 8 2 "7    gray";
        ColorText 8 8 2 "8    white";
        ColorText 9 8 2 "9    white";
        ColorText 10 8 2 "10   black";
        echo "The third parameter is a number ranged from 1 to 9,represents the style of the characters."
        ColorText 10 8 1 "1    lighter,and bold";
        ColorText 10 8 4 "4    draw a line under the string.";
        ColorText 10 8 7 "7    swap the foreground color and the background color";
        ColorText 10 8 9 "9    draw a deleting line";
        ColorText 10 8 9 "others  normal style";
        echo "The fourth parameter is the content you wanna clolor,a string."
}

ColorText 1 8 2 'Test'

#ColorText

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