解决方法
这是可能的Scala 2.11.
使用示例
使用示例
scala> 1 res0: Int = 1 scala> 2 res1: Int = 2 scala> 3 res2: Int = 3 scala> :save xxx scala> :load xxx Loading xxx... res3: Int = 1 res4: Int = 2 res5: Int = 3
您可以:在a之前重置:加载以获得正确的引用结果:
scala> 1 res0: Int = 1 scala> res0 + 1 res1: Int = 2 scala> :save xxx
那天晚些时候…
scala> 7 res0: Int = 7 scala> :reset Resetting interpreter state. Forgetting this session history: 7 Forgetting all expression results and named terms: $intp scala> :load xxx Loading xxx... res0: Int = 1 res1: Int = 2