这是
Scala for the Impatient的一个问题,Arrays的章节陈述为
Given an array of integers,produce a new array that contains all
positive values of the original array,in their original order,
followed by all values that are zero or negative,in their original
order.
我的尝试是
scala> val b = Array(-1,2,3,4,-10,-12) b: Array[Int] = Array(-1,-12) scala> val(positive,negative) = b partition(_ > 0) positive: Array[Int] = Array(2,4) negative: Array[Int] = Array(-1,-12) scala> positive ++ negative res11: Array[Int] = Array(2,-1,-12)
我可以在一条线上做得更好吗？我不确定
解决方法
考虑过滤器和过滤器,如下所示,
b.filter(_ > 0) ++ b.filterNot(_ > 0)
