如何在Scala中覆盖Java varargs方法？

我有一个在 Java中定义的方法,如：

void foo(int x,Thing... things)

我需要在Scala中覆盖它,但这两个都会给出错误：

override def foo(x: Int,things: Thing*)
override def foo(x: Int,things: Array[Thing])

错误指的是<重复...>但我不知道那是什么.

更新

Ugg ……没关系.我在2.10.0,我输入错误的东西,没有方法体.然后我对这个错误信息感到困惑,这对我来说似乎仍然很奇怪.在SBT：

> compile
[info] Compiling 1 Scala source to [...]/target/scala-2.10/classes...
[error] [...]/src/main/scala/Translator.scala:41: class MyMethodVisitor needs to be abstract,since method visitTableSwitchInsn is not defined
[error] (Note that org.objectweb.asm.Label* does not match <repeated...>[org.objectweb.asm.Label])
[error]   class MyMethodVisitor extends MethodVisitor (Opcodes.ASM4) {
[error]         ^

问题是我的visitTableSwitchInsn只是缺少一个体,但错误表明问题是varargs参数的类型.

解决方法

Java的：

package rrs.scribble;

public
class   VA1
{
    public int va1(int... ints) {
        return ints.length;
    }
}

斯卡拉：

package rrs.scribble

class   VA1S
extends VA1
{
  override
  def va1(ints: Int*): Int =
    ints.length * 2
}

SBT：

> ~compile
[info] Compiling 1 Scala source and 1 Java source to …/scribble/target/scala-2.10/classes...
[success] Total time: 4 s,completed Jan 15,2013 3:48:14 PM
1. Waiting for source changes... (press enter to interrupt)

这是Scala 2.10,与@ Travisbrown的评论一致.