Ruby:OptionParser:String Arg&Hash Assignment

使用OptionParser进行字符串参数输入和哈希分配.读取单个参数的多个变量的最佳方法是什么?我如何将这些分配给哈希引用?这是我到目前为止:

large_skus = Hash.new
small_skus = Hash.new

OptionParser.new do |opts|

opts.on("-b","--brands bName1,bName2,bNameN",String,"Check specific brands by name") do |b|
 options[:brands] = b.split(",")
end

opts.on("-l","--large lSku1,lSku2,lSkuN","Large SKUs - List CSVs") do |l|
 options[:large_skus] = l.split(",")
 ##For each sku given
 brandName = options[:brands]
 large_skus[brandName] = l[$sku].to_i
 ##
end

opts.on("-s","--small sSku1,sSku2,sSkuN","Small SKUs - List CSVs") do |s|
 options[:small_skus] = s.split(",")
 ##For each sku given
 brandName = options[:brands]
 small_skus[brandName] = s[$sku].to_i
 ##
end

end.parse!(ARGV)

解决方法

给出一个输入:

ruby test.rb --brands bName1,bNameN --large lSku1,lSkuN --small wQueue1,wQueue2,wQueueN

这段代码

#!/usr/bin/env ruby

require 'ap'
require 'optparse'

options = {}
OptionParser.new do |opts|

  opts.on("-b",Array,"Check specific brands by name") do |b|
    options[:brands] = b
  end

  opts.on("-l","Large SKUs - List CSVs") do |l|
    options[:large_skus] = l
  end

  opts.on("-s","--small wQueue1,wQueueN","Small SKUs - List CSVs") do |s|
    options[:small_skus] = s
  end

end.parse!(ARGV)

ap options

生成输出

{
        :brands => [
        [0] "bName1",[1] "bName2",[2] "bNameN"
    ],:large_skus => [
        [0] "lSku1",[1] "lSku2",[2] "lSkuN"
    ],:small_skus => [
        [0] "wQueue1",[1] "wQueue2",[2] "wQueueN"
    ]
}

请注意,我没有使用每个选项的String类型,而是使用Array.这让OptionParser可以将元素解析成数组.从那时起,由你决定使用数组元素.

相关文章

validates:conclusion,:presence=>true,:inclusion=>{...
一、redis集群搭建redis3.0以前,提供了Sentinel工具来监控各...
分享一下我老师大神的人工智能教程。零基础!通俗易懂!风趣...
上一篇博文 ruby传参之引用类型 里边定义了一个方法名 mo...
一编程与编程语言 什么是编程语言? 能够被计算机所识别的表...
Ruby类和对象Ruby是一种完美的面向对象编程语言。面向对象编...