1.获取列表中出现频率最多的值
a = [1, 2, 3, 1, 5, 4] print (max(set(a), key=a.count)) # 3 from collections import Counter cnt = Counter(a) print cnt.most_common(1) # (3,5)
2. 判断翻转字符串是否相等
str1 = '12345' str2 = '54321' from collections import Counter print (Counter(str1) == Counter(str2)) # True
3. 翻转字符串或数字、列表
a = 'abcdefghigklmnopqrstuvwxyz' print (a[::-1]) # zyxwvutsrqponmlkgihgfedcba print ''.join(list(reversed(a))) # zyxwvutsrqponmlkgihgfedcba num =123456789 print (int(str(num)[::-1])) # 987654321 a=[1,2,3,4,5] print(a[::-1]) # [5,1]