我正在制作一个“预测结果”类型系统,要求用户预测谁将在5个类别中获胜.我将所有数据都放在一张表中,并且我想找出一种方法来计算谁拥有最正确的答案.我知道查询需要什么,但我的语法很乱.有人可以帮帮我吗?
<?PHP $res = array(1,2,3,4,5); //correct results // The idea is to count the number of table fields that match the $res array // and store that count in the 's' column $sql = MysqL_query("SELECT *,s FROM awards_Votes WHERE s+=IF( c1==".$res[0].",1,0),s+=IF( c2==".$res[1].",s+=IF( c3==".$res[2].",s+=IF( c4==".$res[3].",s+=IF( c5==".$res[4].",0) ORDER BY s DESC ") or die(MysqL_error()); ?>