Cakephp db查询结果没有表名,只是MySQL中的简单结果？

我正在使用cakephp,我有一个模特

$db = $this->getDataSource();
$result = $db->fetchAll(
        'SELECT table1.id,table1.title,table1.buy_url,table2.image_file as image,table3.category_id as maincategory,(table4.user_id = "71") AS isfavorite
        FROM table1
        INNER JOIN ...
        LEFT JOIN ...
        LEFT JOIN ...
        where ...);

    return $result;

我得到这样的结果：

{
  "table1": {
    "id": "132","title": "Awesome",},"table2": {
    "image": "image_25398457.jpg"
  },"table3": {
    "maincategory": "3"
  },"table4": {
    "isfavorite": "1"
  }
}

但是我不想显示表格的名称,我更愿意通过以下方式获得结果：

{
    "id": "132","image": "image_25398457.jpg"
    "maincategory": "3"
    "isfavorite": "1"
}

我怎么能得到这个？

谢谢 ！

解决方法

从我所看到的,结果按表名分组.

最简单的选择是：

$merged = call_user_func_array('array_merge',$result);

另一种选择是：

$db = $this->getDataSource();
$result = $db->fetchAll(
    'SELECT * FROM (
        SELECT table1.id,(table4.user_id = "71") AS isfavorite
        FROM table1
        INNER JOIN ...
        LEFT JOIN ...
        LEFT JOIN ...
        where ... '
    ) as final_table
);

return $result;

这就是为什么你只有这样的东西：

{
   "final_table" : {
       "id": "132","image": "image_25398457.jpg"
       "maincategory": "3"
       "isfavorite": "1"
   }
}