我有一个网站,其他人一直在为我编码,我试图了解如何改变一个简单的事情.
我不是webdeveloper,但在最后几天我熟悉了一下PHP,mysql和javascript(我熟悉java).
****问题:****
在我的网站上,我有一个没有搜索按钮的搜索表单(搜索功能适用于输入按下或从自动完成中选择).如何将其更改为仅使用搜索按钮?
使用名为CodeIgniter的框架开发Web.
这是控制器的样子:
public function searchGym() { if($_POST) { $gym_name=$_POST['gym_name']; $gym_name=trim($gym_name," "); $data['details']=$this->user_model->getGymByName($gym_name); $data['gym_name']=$gym_name; $this->load->view('he/searched_gym',$data); } }
这就是模型的样子:
public function getGymByName($query_string) { $query_string=MysqL_real_escape_string($query_string); $query=$this->db->query("select * from gym_members_table where member_title like '%$query_string%'"); return $query->result_array(); } </code>
<div class="search-home"> <input type="text" onkeypress="gymhandle(event);" class="form-control gym_search" id="gym" name="gym" placeholder=" Search by Name " > <div class="autosuggest1"></div> <div class="autosuggest"></div> </div> <script> function settextBox(rval){ $('.autosuggest').hide(); $('#gym').val(rval); $('#gym_search2').val(rval); searchGymByName(rval); } $(document).ready(function(){ $('.autosuggest').hide(); $('#gym').keyup(function(e) { var code = (e.keyCode || e.which); // do nothing if it's an arrow key if(code == 37 || code == 38 || code == 39 || code == 40 || code==13) { return; } var search_term = $(this).val(); var getdata = { 'search_term': search_term}; if(search_term!=''){ $.ajax({ url: "<?PHP echo site_url('hebrew/searchGymAuto');?>",data: getdata,type: 'POST',success: function(data){ $('.autosuggest').show(); $('.autosuggest').html(data); } }); } else { $('.autosuggest').hide(); } }); }); $('.autosuggest').hide(); function searchGymByName(rval) { $('.autosuggest').hide(); var gym_name=rval; $.ajax({ url:"<?PHP echo site_url();?>hebrew/searchGym",type: "POST",data:{gym_name: gym_name},success:function(res){ $('html,body').animate({ scrollTop: 0 },0); $("#ajax-map").hide(); $("#city").val(''); $("#city1").val(''); $("#ajax-page-hide").show(); $("#ajax-page-hide").html(res); } }); }
谢谢!!
解决方法
您可以在这些字段上取消输入按键,如下所示:
$('.gym_search').keypress(function(e){ if ( e.which == 13 ) return false; //or... if ( e.which == 13 ) e.preventDefault(); });