经测试代码如下:
/**
* 计算到指定日期还有多少天
*
* @param
* @arrange (编程之家) jb51.cc
**/
function countdays($d)
{
$olddate = substr($d,4);
$newdate = date(Y) ..$olddate;
$nextyear = date(Y)+1 ..$olddate;
if($newdate > date(Y-m-d))
{
$start_ts = strtotime($newdate);
$end_ts = strtotime(date(Y-m-d));
$diff = $end_ts - $start_ts;
$n = round($diff / 86400);
$return = substr($n,1);
return $return;
}
else
{
$start_ts = strtotime($nextyear);
$end_ts = strtotime(date(Y-m-d));
$diff = $end_ts - $start_ts;
$n = round($diff / 86400);
$return = substr($n,1);
return $return;
}
}