php 不使用JavaScript调用Google Analytics的简单示例

感兴趣的小伙伴，下面一起跟随编程之家 jb51.cc的小编来看看吧。
经测试代码如下：

<?PHP
/**
 * 不使用JavaScript调用Google Analytics
 *
 * @param 
 * @arrange (编程之家) jb51.cc
 **/

$var_utmac=GOOGLE_ANALYTICS_CODE; //enter the new urchin code
$var_utmhn=WEB_DOMAIN; //enter your domain
$var_utmn=rand(1000000000,9999999999);//random request number
$var_cookie=rand(10000000,99999999);//random cookie number
$var_random=rand(1000000000,2147483647); //number under 2147483647
$var_today=time(); //today
$var_referer=$_SERVER['HTTP_REFERER']; //referer url

$var_uservar=$storeinfo[storeid]; //enter your own user defined variable
$var_utmp=http://.$_SERVER['HTTP_HOST'].$_SERVER['REQUEST_URI'];

$urchinUrl='http://www.google-analytics.com/__utm.gif?utmwv=1&utmn='.$var_utmn.'&utmsr=-&utmsc=-&utmul=-&utmje=0&utmfl=-&utmdt=-&utmhn='.$var_utmhn.'&utmr='.$var_referer.'&utmp='.$var_utmp.'&utmac='.$var_utmac.'&utmcc=__utma%3D'.$var_cookie.'.'.$var_random.'.'.$var_today.'.'.$var_today.'.'.$var_today.'.2%3B%2B__utmb%3D'.$var_cookie.'%3B%2B__utmc%3D'.$var_cookie.'%3B%2B__utmz%3D'.$var_cookie.'.'.$var_today.'.2.2.utmccn%3D(direct)%7Cutmcsr%3D(direct)%7Cutmcmd%3D(none)%3B%2B__utmv%3D'.$var_cookie.'.'.$var_uservar.'%3B';

$handle = fopen ($urchinUrl,r);
$test = fgets($handle);
fclose($handle);

/*** 来自：编程之家 jb51.cc（jb51.cc） ***/ 
?>

不适用JavaScript调用Google Analytics，这段代码适用于浏览器不支持JS时使用