PHP提取数据库内容中的图片地址并循环输出

PHP 2018-12-30

<div class="codetitle"><a style="CURSOR: pointer" data="23199" class="copybut" id="copybut23199" onclick="doCopy('code23199')"> 代码如下:

<div class="codebody" id="code23199">
/
1 (?s) 代表 Pattern.DOTALL,也就是匹配换行，允许 img里出现在多行
2 .?代表非贪婪匹配任意字符，直到后面的条件出现
3 ?: 代表这个匹配但不被捕获，也就是不在结果出现 [.gif|.jpg] 是或者的意思
/
$pattern="/<img.?src=\'|\"[\'|\"].?[\/]?>/";
$str='<p style="padding: 0px; margin-top: 0px; margin-bottom: 0px; line-height: 200%;"><img border="0" src="upfiles/2009/07/1246430143_4.jpg" alt=""/>
<p style="padding: 0px; margin-top: 0px; margin-bottom: 0px; line-height: 200%;"><img border="0" src="upfiles/2009/07/1246430143_3.jpg" alt=""/>
<p style="padding: 0px; margin-top: 0px; margin-bottom: 0px; line-height: 200%;"><img border="0" src="upfiles/2009/07/1246430143_1.jpg" alt=""/>
';
preg_match_all($pattern,$str,$match);
print_r($match);
/
Array
(
[0] => Array
(
[0] => <img border="0" src="upfiles/2009/07/1246430143_4.jpg" alt=""/>
[1] => <img border="0" src="upfiles/2009/07/1246430143_3.jpg" alt=""/>
[2] => <img border="0" src="upfiles/2009/07/1246430143_1.jpg" alt=""/>
)
[1] => Array
(
[0] => upfiles/2009/07/1246430143_4.jpg
[1] => upfiles/2009/07/1246430143_3.jpg
[2] => upfiles/2009/07/1246430143_1.jpg
)
)
*/

PHP 图片地址

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