PHP获取一年有几周以及每周开始日期和结束日期

最近接了一个项目，其中有一需求是用PHP获取一年有几周以及每周开始日期和接触日期。在网上找些资料没有合适的，于是自己做了一份，下面通过两种方式实现PHP获取一年有几周以及每周开始日期和结束日期

代码一：

rush:PHP;"> PHP header("Content-type:text/html;charset=utf-8"); date_default_timezone_set("Asia/Shanghai"); $year = (int)$_GET['year']; $week = (int)$_GET['week']; $weeks = date("W",mktime(0,12,28,$year)); echo $year . '年一共有' . $weeks . '周
'; if ($week > $weeks || $week <= 0) { $week = 1; } if ($week < 10) { $week = '0' . $week; } $timestamp['start'] = strtotime($year . 'W' . $week); $timestamp['end'] = strtotime('+1 week -1 day',$timestamp['start']); echo $year . '年第' . $week . '周开始时间戳：' . $timestamp['start'] . '
'; echo $year . '年第' . $week . '周结束时间戳：' . $timestamp['end'] . '
'; echo $year . '年第' . $week . '周开始日期：' . date("Y-m-d",$timestamp['start']) . '
'; echo $year . '年第' . $week . '周结束日期：' . date("Y-m-d",$timestamp['end']); ?>

代码二：

rush:PHP;"> setISODate($year,53); return ($date->format("W") === "53" ? 53 : 52); } function weekday($custom_date) { $week_start = date('d-m-Y',strtotime('this week monday',$custom_date)); $week_end = date('d-m-Y',strtotime('this week sunday',$custom_date)); $week_array[0] = $week_start; $week_array[1] = $week_end; return $week_array; } echo '
Weeks in 2013
' . getIsoWeeksInYear(2013); $weekday = weekday(strtotime(date('d-m-Y',strtotime('5-8-2013')))); echo '
10-8-2013'; echo '
Start: ' . $weekday[0]; echo '
End: ' . $weekday[1]; ?>

以上本文的全部内容，希望对大家学习PHP获取一年有几周以及每周开始日期和结束日期，有所帮助。