核心代码：
$sYear = substr($DateStart,4);
$eYear = substr($DateEnd,4);
$sMonth = substr($DateStart,2);
$eMonth = substr($DateEnd,2);
$sDay = substr($DateStart,2);
$eDay = substr($DateEnd,2);
$startTime = $this->fmDatetime($DateStart);
$endTime = $this->fmDatetime($DateEnd);
$<a href="https://www.jb51.cc/tag/dis/" target="_blank" class="keywords">dis</a> = $endTime-<a href="https://www.jb51.cc/tag/start/" target="_blank" class="keywords">$start</a>Time;//得到俩个时<a href="https://www.jb51.cc/tag/jiande/" target="_blank" class="keywords">间的</a>秒数
$d = ceil($<a href="https://www.jb51.cc/tag/dis/" target="_blank" class="keywords">dis</a>/(24*60*60));//得到天数
$rs['day'] = $d;//天数
$rs['hour'] = ceil($<a href="https://www.jb51.cc/tag/dis/" target="_blank" class="keywords">dis</a>/(60*60));//小时
$rs['minute'] = ceil($<a href="https://www.jb51.cc/tag/dis/" target="_blank" class="keywords">dis</a>/60);//分钟
$rs['second'] = $<a href="https://www.jb51.cc/tag/dis/" target="_blank" class="keywords">dis</a>;//秒数
$rs['week'] = ceil($d/7);//周
$tem = ($eYear-$sYear)*12;//月份
$tem1 = $eYear-$sYear;//年
if($eMonth-$sMonth<0){//月份相减为负
$tem +=($eMonth-$sMonth);
}else if($eMonth==$sMonth){//月份相同
if($eDay-$sDay>=0){
$tem ++;
$tem1++;
}
}else if($eMonth-$sMonth>0){//月份相减正负
$tem1++;
if($eDay-$sDay>=0){//且日期相减为正数
$tem +=($eMonth-$sMonth)+1;
}else{
$tem +=($eMonth-$sMonth);
}
}
$rs['month'] = $tem;
$rs['year'] = $tem1;
return $rs;
}
}
一年多一天，返回的是2年，一个月多一天返回的是2个月，以此推......项目需要，才做此出来，开始我也到网上找这样的例子，但大家都是把年就按365天来算，月就按30天来算，这样算出来的结果肯定是没用的，年有可能是366天，月有可能是31，29，28都有可能
