即使发生错误,是否可以使file_get_contents显示实际响应?
否则很难调试.例如,假设您有以下代码:
$url = 'https://api.twitter.com/oauth/request_token';
$data = array();
$options = array(
'http' => array(
'header' => "Content-type: application/x-www-form-urlencoded\r\n",
'method' => 'POST',
'content' => http_build_query($data),
),
);
$context = stream_context_create($options);
$result = @file_get_contents($url, false, $context);
var_dump($result);
var_dump($http_response_header);
这显示结果和HTTP标头的NULL,但我想得到Twitter发回的实际消息(应该是像验证oauth签名和令牌的失败),如果你尝试在你的方法中加载https://api.twitter.com/oauth/request_token
就会得到浏览器.
解决方法:
'ignore_errors' => true
所以你会得到的
$options = array(
'http' => array(
'header' => "Content-type: application/x-www-form-urlencoded\r\n",
'method' => 'POST',
'content' => http_build_query($data),
'ignore_errors' => true
)
);