我有变量$EDate,我使用strtotime函数与这个变量具有不同的值,结果如下:
$EDate = 10-21-2013; echo "strtotime($EDate)"; the result = nothing and the type is boolean
$EDate = 09-02-2013; echo "strtotime($EDate)"; the result = 1360386000 and the type is integer
$EDate = 09-30-2013; echo "strtotime($EDate)"; the result = nothing and the type is boolean
$EDate = 09-30-2013; echo "strtotime($EDate)"; the result = nothing and the type is boolean
$EDate = 07-02-2014; echo "strtotime($EDate)"; the result = 1391749200 and the type is integer
$EDate = 10-12-2014; echo "strtotime($EDate)"; the result = 1418187600 and the type is integer
任何人都可以解释这个以及如何避免布尔结果吗?
解决方法:
Dates in the m/d/y or d-m-y formats are disambiguated by looking at the separator between the varIoUs components: if the separator is a slash (/), then the American m/d/y is assumed; whereas if the separator is a dash (-) or a dot (.), then the European d-m-y format is assumed.
您的代码假定日期采用d-m-y格式,并且由于月份值不正确,将返回FALSE:
var_dump(strtotime('10-21-2013')); // no month 21
var_dump(strtotime('09-30-2013'));
var_dump(strtotime('09-30-2013'));
如果您希望能够使用自定义格式,请使用DateTime::createFromFormat()
:
$date = DateTime::createFromFormat('m-d-Y', '10-21-2013');
echo $date->format('U');