php – 如何在sql中按两列分组？

我有两个表,一个是“事件”,第二个是“门票”：

活动表：

============================
| event_id |   event_name  |
============================
|   101    | Running Event |
|   102    | Cycling Event |
============================

门票表：

==============================================================
| ticket_id | event_id | ticket_number | ticket_generate_date|
==============================================================
|    1      |    101   |    40001      |  2018-08-21 17:05   |
|    2      |    101   |    40002      |  2018-08-21 18:05   |
|    3      |    102   |    40001      |  2018-08-21 19:05   |
|    4      |    101   |    40003      |  2018-08-23 20:05   |
|    5      |    101   |    40004      |  2018-08-24 20:05   |
==============================================================

现在我想运行查询,以便我的输出如下所示：

================================================
| count ticket |   event_name  | day wise data |
================================================
|       2      | Running Event |  2018-08-21   |
|       1      | Cycling Event |  2018-08-21   |
|       1      | Running Event |  2018-08-23   |
|       1      | Running Event |  2018-08-24   |
================================================

我尝试了以下查询：

SELECT COUNT(ticket_id), ticket_generate_date FROM Tickets 
WHERE ticket_generate_date >= DATE_FORMAT(curdate(), '%Y-%m-01') 
GROUP BY DATE_FORMAT(ticket_generate_date, '%d-%b');

解决方法:

您只需要将第二个组选项添加到您已使用逗号的选项中.

我还使用了别名和INNER JOIN来获取事件名称.

SELECT 
    COUNT(t.ticket_id),
    e.event_name,
    DATE_FORMAT(t.ticket_generate_date, '%Y-%m-%d') as day_wise
FROM 
    Tickets t
INNER JOIN
    Events e ON e.event_id = t.event_id
WHERE 
    t.ticket_generate_date >= DATE_FORMAT(curdate(), '%Y-%m-01') 
GROUP BY 
    DATE_FORMAT(t.ticket_generate_date, '%Y-%m-%d'), e.event_name

它在这里工作：
http://sqlfiddle.com/#!9/b235c/1/0