php – 如何实现这一点：object-> object-> property

我看到很多代码都是这样的调用.

一个例子：

$person->head->eyes->color = "brown";
$person->head->size = 10;
$person->name = "Daniel";

我如何实现上面所写的内容？

解决方法:

这只意味着$person,$person-> head和$person->眼睛各自拥有属于其他对象的属性. head是$person的属性,eye是$person-> head的属性,依此类推.

因此,当您设置$person-> head-> size时,您设置的是$person-> head的size属性,这意味着$person-> head必须是一个对象.换句话说,声明$person-> head-> size = 10;表示将$person的head属性的size属性设置为10.

示例代码：

<?PHP

class Eyes
{
    var $color = null;
}

class Head
{
    var $eyes = null;
    var $size = null;


    function __construct()
    {
        $this->eyes = new Eyes();
    }
}

class Person
{
    var $head = null;
    var $name = null;

    function __construct()
    {
        $this->head = new Head();
    }
}

$person = new Person();
$person->head->eyes->color = "brown";
$person->head->size = 10;
$person->name = "Daniel";

var_dump($person);

这输出：

class Person#1 (2) {
  public $head =>
  class Head#2 (2) {
    public $eyes =>
    class Eyes#3 (1) {
      public $color =>
      string(5) "brown"
    }
    public $size =>
    int(10)
  }
  public $name =>
  string(6) "Daniel"
}