如何使用MySQL获取最新日期？我试过最大但我没有得到我想要的结果.我的表看起来像这样：
+---------+---------+-----------------------+--------+------------+---------+
| Name | idStore | Name | idItem | date | price |
+---------+---------+-----------------------+--------+------------+---------+
| walmart | 1 | Red DelicIoUs Apples | 1 | 2011-10-22 | 0.98000 |
| walmart | 1 | Red DelicIoUs Apples | 1 | 2011-10-28 | 0.98000 |
| walmart | 1 | Red DelicIoUs Apples | 1 | 2011-10-28 | 0.98000 |
| walmart | 1 | Red DelicIoUs Apples | 1 | 2011-11-22 | 0.98000 |
| walmart | 1 | Honeycrisp Apples | 2 | 2011-10-22 | 1.98000 |
| walmart | 1 | Sonya Apples | 3 | 2011-10-22 | 2.88000 |
| walmart | 1 | Gold DelicIoUs Apples | 4 | 2011-10-22 | 0.98000 |
| walmart | 1 | Sweet Tango Apples | 5 | 2011-10-22 | 2.48000 |
| walmart | 1 | Granny Smith Apples | 6 | 2011-10-22 | 1.28000 |
| walmart | 1 | Fugi Apples | 7 | 2011-10-22 | 1.38000 |
+---------+---------+-----------------------+--------+------------+---------+
我想得到这张桌子：
+---------+---------+-----------------------+--------+------------+---------+
| Name | idStore | Name | idItem | date | price |
+---------+---------+-----------------------+--------+------------+---------+
| walmart | 1 | Red DelicIoUs Apples | 1 | 2011-11-22 | 0.98000 |
| walmart | 1 | Honeycrisp Apples | 2 | 2011-10-22 | 1.98000 |
| walmart | 1 | Sonya Apples | 3 | 2011-10-22 | 2.88000 |
| walmart | 1 | Gold DelicIoUs Apples | 4 | 2011-10-22 | 0.98000 |
| walmart | 1 | Sweet Tango Apples | 5 | 2011-10-22 | 2.48000 |
| walmart | 1 | Granny Smith Apples | 6 | 2011-10-22 | 1.28000 |
| walmart | 1 | Fugi Apples | 7 | 2011-10-22 | 1.38000 |
+---------+---------+-----------------------+--------+------------+---------+
我很难搞清楚这一点.谢谢！
解决方法:
在线示例查询
http://data.stackexchange.com/stackoverflow/q/118881/how-can-i-get-the-most-resent-date-using-mysql
SELECT NameStore, idStore, Name, idItem, max(date) AS date, price
FROM tablename
GROUP by NameStore, idStore, Name, idItem, price
ORDER BY date DESC, idItem ASC
