php – 如何使用jQuery datatable插件实现这种复杂的搜索？

我正在尝试创建一个可搜索的界面,我的后端包括三个MySQL 数据库表：

tbl_country

MysqL> select * from tbl_country;
+--------------+---------------+
| country_code | country       |
+--------------+---------------+
| AFG          | AFGHANISTAN   |
| AUS          | AUSTRALIA     |
| CAN          | CANADA        |
| GBR          | GREAT BRITAIN |
| IND          | INDIA         |
| USA          | USA           |
+--------------+---------------+
6 rows in set (0.00 sec)

tbl_state

MysqL> select * from tbl_state;
+----------+------------------+--------------+
| state_id | state            | country_code |
+----------+------------------+--------------+
|        1 | Maharashtra      | IND          |
|        2 | Delhi            | IND          |
|        3 | West Bengali     | IND          |
............
|       51 | Queensland       | AUS          |
+----------+------------------+--------------+
33 rows in set (0.00 sec)

tbl_city

MysqL> select * from tbl_city;
+---------+----------+--------------------+
| city_id | state_id | city               |
+---------+----------+--------------------+
|       1 |        1 | Mumbai (Bombay)    |
|       2 |        1 | Nagpur             |
.......
|      84 |       37 | Edinburgh          |
|     122 |       44 | Cardiff            |
|     127 |       46 | Melbourne          |
|     130 |       48 | Perth              |
|     131 |       49 | Adelaide           |
|     132 |       50 | Canberra           |
|     133 |       51 | Brisbane           |
|     134 |       51 | Gold Coast         |
+---------+----------+--------------------+
54 rows in set (0.00 sec)

我有我的MysqL 数据库架构和值,如SQL Fiddle所示

我的搜索需要从我可以根据任何给定的城市或州详细信息搜索所有国家/地区获得单一界面.

我正在尝试使用此查询,它正确地提供了我想要获取的输出：

SELECT 
-- tbl_country
c.country_code, c.country,

-- tbl_state
CAST(GROUP_CONCAT(s.state SEParaTOR ',') AS CHAR) as state,
-- tbl_city
CAST(GROUP_CONCAT(ct.city SEParaTOR ',') AS CHAR) as city

-- tbl_papers
FROM tbl_country c
LEFT JOIN tbl_state s ON s.country_code = c.country_code
LEFT JOIN tbl_city ct ON ct.state_id = s.state_id

GROUP BY (c.country_code);

我使用的是Datatable 插件,它非常强大且易于使用,但每当我尝试使用搜索过滤器时,它现在将工作,因为数据表的Server Side PHP class尝试创建一个动态查询,其中where条件基于绑定列.

查询绑定数据表,如第一行所示,因为没有搜索完成：

动态查询是这样的：

SELECT    sql_calc_found_rows `c`.`country_code`,
          `c`.`country`,
          group_concat(`s`.`state` separator "," ) AS state,
          group_concat(`ct`.`city` separator ",")  AS city
FROM      `tbl_country`                            AS `c`
LEFT JOIN `tbl_state`                              AS `s`
ON        (
                    `s`.`country_code` = `c`.`country_code`)
LEFT JOIN `tbl_city` AS`ct`
ON        `ct`.`state_id` = `s`.`state_id`
WHERE     (
                    `c`.`country_code` LIKE :binding_0
          OR        `c`.`country` LIKE :binding_1
          OR        group_concat(`s`.`state` separator ",") LIKE :binding_2
          OR        group_concat(`ct`.`city` separator ",") LIKE :binding_3)
GROUP BY  `c`.`country_code`
ORDER BY  `c`.`country_code` ASC limit 0,
          10

这显然给出了如下所示的错误：

无论如何,我可以使用PHP和datatable插件根据上述场景中给定的城市和州和国家详细信息进行过滤/搜索.可能是我需要更改我的查询结构！

解决方法:

我假设您正在使用ssp.class.PHP来处理服务器端的数据.

类ssp.class.PHP 不支持包含JOIN和子查询的复杂查询,但有一种解决方法.诀窍是在$table deFinition中使用如下所示的子查询.

$table = <<<EOT
 (
    SELECT 
    c.country_code, 
    c.country,
    CAST(GROUP_CONCAT(s.state SEParaTOR ',') AS CHAR) as state,
    CAST(GROUP_CONCAT(ct.city SEParaTOR ',') AS CHAR) as city
    FROM tbl_country c
    LEFT JOIN tbl_state s ON s.country_code = c.country_code
    LEFT JOIN tbl_city ct ON ct.state_id = s.state_id
    GROUP BY (c.country_code)
 ) temp
EOT;

$primaryKey = 'id';

$columns = array(
   array( 'db' => 'country_code', 'dt' => 0 ),
   array( 'db' => 'country', 'dt' => 1 ),
   array( 'db' => 'state', 'dt' => 2 ),
   array( 'db' => 'city', 'dt' => 3 )
);

$sql_details = array(
   'user' => '',
   'pass' => '',
   'db'   => '',
   'host' => ''
);

require( 'ssp.class.PHP' );
echo json_encode(
   ssp::simple( $_GET, $sql_details, $table, $primaryKey, $columns )
);

您还需要编辑ssp.class.PHP并用FROM $table替换FROM` $table`的所有实例以删除反引号.

还有github.com/emran/ssp个存储库,其中包含支持JOIN的增强型ssp.class.PHP.

链接

php – 如何使用jQuery datatable插件实现这种复杂的搜索？

相关文章