注意：数组转换为字符串 – PHP和mySQL

我一直在读这里与此相关的每一个帖子,但我总是弄错了.

请帮忙,因为我总是得到错误

“Notice: Array to string conversion” in line “$address[] =
mysql_result($row, 0 );”

下面.请帮忙.

if ($p_address=MysqL_query($email))
{
$address = array();

while($row = MysqL_fetch_assoc($p_address))
{     
 $address[] = MysqL_result($row, 0 );
}  

$all_address = implode(',', $address);

解决方法:

改变这一行

 $address[] = MysqL_result($row, 0 );

对此：

 $address[] = $row;

然后要查看新$address数组中可用的键和值,您可以执行以下操作：

 print_r($address);

为了保持implode()的功能,请执行以下操作：

for ($i = 0; $i < count($address); $i++) {
  $all_address[] = implode(',', $address[$i]);
}

最终输出：

if ($p_address=MysqL_query($email))
{
$address = array();

while($row = MysqL_fetch_assoc($p_address))
{     
 $address[] = $row;
}

for ($i = 0; $i < count($address); $i++) {
  $all_address[] = implode(',', $address[$i]);
}

// Example for outputting on screen:
foreach ($all_address as $aa) {
  print $aa . "<br/>\n";
}
}

希望有帮助……