我有一个名为指定的下拉列表,用户将选择其中一个,并在提交后,如果有一些错误,那么我想选择所选的指定.
我在laravel 5.4中使用它.
调节器
$info = DB::table("designation")
->where('status','=',1)
->pluck("name","id");
return view('regUser.add',['check' => 'userList','designation' => $info]);
查看文件
<div class="form-group {{ $errors->has('designation') ? ' has-error' : '' }}">
<label for="designation">Designation</label>
<select id="designation" name="designation" class="form-control">
<option value="">--- Select designation ---</option>
@foreach ($designation as $key => $value)
<option value="{{ $key }}" />{{ $value }}</option>
@endforeach
</select>
@if ($errors->has('designation'))
<span class="help-block">
<strong>{{ $errors->first('designation') }}</strong>
</span>
@endif
</div>
现在,如果验证器发现了一些错误,那么我想选择之前选择的错误.
我怎样才能在laravel 5.4中实现这个目标.
在提交表单之后,它来到addUserinformation函数,在那里我验证具有这段代码的用户信息
public function addUserinformation(Request $request){
$this->validate($request, [
'name' => 'required|string|min:5',
'email' => 'required|string|email|unique:users,email',
'designation' => 'required|exists:designation,id',
'password' => 'required|min:6',
'confirm_password' => 'required|same:password',
'userimage' => 'required|image',
]);
$selectedID = $request->input('designation');
}
解决方法:
Larvel在验证错误时将输入传回.您可以使用旧的帮助程序函数来获取以前的表单值.一个简单的比较就可以了.
<div class="form-group {{ $errors->has('designation') ? ' has-error' : '' }}">
<label for="designation">Designation</label>
<select id="designation" name="designation" class="form-control">
<option value="">--- Select designation ---</option>
@foreach ($designation as $key => $value)
<option value="{{ $key }}" {{ old('designation') == $key ? 'selected' : ''}}>{{ $value }}</option>
@endforeach
</select>
@if ($errors->has('designation'))
<span class="help-block">
<strong>{{ $errors->first('designation') }}</strong>
</span>
@endif
</div>