我试图从以下查询获得所需的结果,但它似乎没有工作…
SELECT disTINCT
u.user_name as user_name,
u.total_points as total_points,
u.user_id as user_id,
COUNT(a.id) as user_total_articles_published,
COUNT(r.id) as user_total_replies_published,
COUNT(v.id) as user_total_Votes_done
FROM users as u
LEFT JOIN articles as a ON u.user_id=a.user_id
LEFT JOIN replies as r ON u.user_id=r.user_id
LEFT JOIN Votes as v ON u.user_id=v.user_id
GROUP BY u.user_id
ORDER BY u.total_points DESC
LIMIT 10
如果我删除最后2个LEFT jOINS,查询将起作用…其他2的错误是什么?我是否必须使用其他方法才能工作?
谢谢
解决方法:
我想通过’不工作’你的意思是查询返回太多记录?这是因为联接的组合.您将返回每篇文章记录的每个回复,因此数字会相乘.您可以通过在COUNT中使用disTINCT来解决此问题.这样,您可以计算唯一ID,因此您只需计算一次每篇文章:
COUNT(distinct a.id) as user_total_articles_published,
COUNT(distinct r.id) as user_total_replies_published,
COUNT(distinct v.id) as user_total_Votes_done
[编辑]
一个可能更快的解决方案,无需disTINCT和GROUP BY:
SELECT
u.user_name as user_name,
u.total_points as total_points,
u.user_id as user_id,
(SELECT COUNT(a.id) FROM articles a
WHERE a.user_id = u.user_id) as user_total_articles_published,
(SELECT COUNT(r.id) FROM replies r
WHERE r.user_id = u.user_id) as user_total_replies_published,
(SELECT COUNT(v.id) FROM Votes v
WHERE v.user_id = u.user_id) as user_total_Votes_done
FROM users as u
ORDER BY u.total_points DESC
LIMIT 10