使用PHP以工作日格式返回给定月份的第一天

因此,为了创建日历,我想要确定任何给定月份的第一个工作日是什么.我有以下代码：

    $today=date('Y-m-d');

    IF (!$_GET) {
    $Now=time();
    }
    ELSE {
    $Now=strtotime($_GET['month']);
    }

    // the month in question is linked through a GET form variable in the Ymd format

    $thisdayNow=date('Y-m-d', $Now);

    $monthyear=date('F Y', $Now);

    $thismonth=date('M', $Now);

    $thisyear=date('Y', $Now);

    $weekday=date('l', $Now);

    $firstday = new DateTime($thisdayNow);
    $firstday->modify('first day of this month');
    $work=$firstday->format('Ymd');
    $firstweekday=date('l', $work);
    $firstdayweek=date('w', $work);

    ECHO 'Today is '.$thisdayNow.'<br />';

    ECHO 'The first day of the month was '.$work.'<br />';

    ECHO 'Today is a '.$weekday.'.<br />';

    ECHO 'The first day of this month was a '.$firstweekday.', the '.$firstdayweek.'th day of the week.<br />';

这会返回：

Today is 2013-05-06

The first day of the month was 20130501

Today is a Monday.

The first day of this month was a Saturday, the 6th day of the week.

There are 31 days this month.

对我所做错的任何帮助都将不胜感激!!!

解决方法:

$inputMonth = '2013-05-01';
$month = date("m" , strtotime($inputMonth));
$year = date("Y" , strtotime($inputMonth));
$getdate = getdate(mktime(null, null, null, $month, 1, $year));
echo $getdate["weekday"];

生产：
星期三

如果问题仍然存在.
问题可能在这里：

IF (!$_GET) {

应该

if (!isset($_GET['month'])) {

这样,您总是分配当前时间(),这就是为什么月份的第一天始终是当前月份的原因.

http://phpfiddle.org/main/code/4ja-928