Array ( [740073] => Leetee Cat 1 [720102] => cat 1 subcat 1 [730106]
=> subsubcat [740107] => and another [730109] => test cat )
我想删除元素之后的所有元素元素,键是’720102′.所以阵列将成为:
Array ( [740073] => Leetee Cat 1 [720102] => cat 1 subcat 1 )
我怎么做到这一点?到目前为止我只有这个…
foreach ($category as $cat_id => $cat){
if ($cat_id == $cat_parent_id){
//remove this element in array and all elements that come after it
}
}
[编辑]第一个答案似乎适用于大多数情况,但不是全部.如果原始数组中只有两个项,则只删除第一个元素,但不删除后面的元素.如果只有两个元素
Array ( [740073] => Leetee Cat 1 [740102] => cat 1 subcat 1 )
变
Array ( [740073] => [740102] => cat 1 subcat 1 )
为什么是这样?似乎每当$position为0时.
解决方法:
就个人而言,我会使用array_keys
,array_search
和array_splice
.通过使用array_keys检索键列表,可以将所有键作为数组中的值以0的键开头.然后使用array_search查找键的键(如果这有任何意义)将成为原始数组中键的位置.最后,array_splice用于删除该位置之后的任何数组值.
PHP:
$categories = array(
740073 => 'Leetee Cat 1',
720102 => 'cat 1 subcat 1',
730106 => 'subsubcat',
740107 => 'and another',
730109 => 'test cat'
);
// Find the position of the key you're looking for.
$position = array_search(720102, array_keys($categories));
// If a position is found, splice the array.
if ($position !== false) {
array_splice($categories, ($position + 1));
}
var_dump($categories);
输出:
array(2) {
[0]=>
string(12) "Leetee Cat 1"
[1]=>
string(14) "cat 1 subcat 1"
}