php – 按日期显示MySQL结果

我有这个mysql表：

+--------------------+---------+-------+
|      date          | query   | count |
|--------------------+---------+-------|
|2012-11-18 09:52:00 | Michael |   1   |
|2012-11-18 10:47:10 |  Tom    |   2   |
|2012-11-17 15:02:12 |  John   |   1   |
|2012-11-17 22:52:10 |  Erik   |   3   |
|2012-11-16 09:42:01 |  Larry  |   1   |
|2012-11-16 07:41:33 |  Kate   |   1   |
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

等等.我可以通过以下代码简单地获取结果并按日期在一行中对它们进行排序：

$queries = MysqL_query("SELECT * FROM my_tables ORDER BY date DESC LIMIT 20"); 
while($row = MysqL_fetch_array($queries)){
    echo "Name ".$row['query']."";
}

但是如何显示按特定日期排序的表中的元素,如下所示：

In 2012-11-18:
Michael
Tom

In 2012-11-17:
John
Erik

In 2012-11-16:
Larry
Kate

等等.谢谢！

解决方法:

这是PHP代码：

$query = MysqL_query("SELECT date, query FROM table6 ORDER BY date DESC LIMIT 20");
$group_date = null;
while ($row = MysqL_fetch_assoc($query)) {
    if ($group_date !== substr($row["date"], 0, 10)) {
        $group_date = substr($row["date"], 0, 10);
        echo "<h1>$group_date</h1>\n";
    }
    echo "${row['query']}<br>\n";
}

输出：

2012-11-18

Tom

Michael

2012-11-17

Erik

John

2012-11-16

Larry

Kate

请注意,虽然此代码将行“按行”分组,但可以轻松地将其扩展为按多列分组行.留下来作为锻炼.