显示错误消息PHP Mysql

我无法使最后2个回声工作,即使更新查询失败,它仍然显示成功.如果有人对此代码有任何建议,请在任何一行进行改进,请做！

<?PHP
        if(!empty($_POST['username']) && !empty($_POST['answer']))  { 
            $username = $_POST['username'];
            $idfetch = MysqL_query("SELECT id FROM users WHERE username ='$username'") //check it
            or die(MysqL_error());
            $fetched = MysqL_fetch_array($idfetch);  
            $id = $fetched['id']; //get users id for checking
            $answer = $_POST['answer'];
            $password = (MysqL_real_escape_string($_POST['password']));
            $confpass = (MysqL_real_escape_string($_POST['confpass']));
            if ($password != $confpass) {
                echo ("Passwords do not match, please try again.");
                exit;
            }
            $updatequery = MysqL_query("UPDATE users SET PASSWORD='$password' WHERE id='$id' AND username='$username' AND answer='$answer'");
            if($updatequery)  {  
                echo "<h1>Success</h1>";  
                echo "<p>Your account password was successfully changed. Please <a href=\"login.PHP\">click here to login</a>.</p>";  
            }  
            else  {  
                echo "<h1>Error</h1>";  
                echo "<p>Sorry, but a field was incorrect.</p>";  
            }  
       } 
?>

提前致谢！

解决方法:

MysqL_query("UPDATE users SET PASSWORD='$password' WHERE id='$id' AND username='$username' AND answer='$answer'") or die(MysqL_error()."update Failed");

并使用

MysqL_affected_rows()

Returns the number of affected rows on success, and -1 if the last query Failed.