http://domain.com/book/chapter/topic/article
我会使用参数的Laravel路线:
Route :: get(‘/ {book} / {chapter} / {topic} / {article}’,’controller @ func’)
在Laravel中,是否有可能只有一个规则可以满足图书结构中未知数量的级别(类似于this question)?这意味着哪里有子文章,子分文章等.
解决方法:
您需要的是可选的路由参数:
//in routes.PHP
Route::get('/{book?}/{chapter?}/{topic?}/{article?}', 'controller@func');
//in your controller
public function func($book = null, $chapter = null, $topic = null, $article = null) {
...
}
有关详细信息,请参阅文档:http://laravel.com/docs/5.0/routing#route-parameters
更新:
//in routes.PHP
Route::get('/{book?}/{chapter?}/{topic?}/{article?}/{sublevels?}', 'controller@func')->where('sublevels', '.*');
//in your controller
public function func($book = null, $chapter = null, $topic = null, $article = null, $sublevels = null) {
//this will give you the array of sublevels
if (!empty($sublevels) $sublevels = explode('/', $sublevels);
...
}