MySQL和PHP – 如何显示字段值等于x的所有行？

我有一个包含以下字段的数据库表(ff_projections)：

ID  Player  Position    Team    Pass_Yds    Pass_TDs    Int_Thrown  rush_Yds    rush_TDs    Rec_Yds Rec_TDs Receptions  Fumbles Extra_Pts   FG  Sacks   Int_Caught  Def_TD  ST_TD   Shutouts    Overall_Pts Total_Fantasy_Pts

我想要的是显示Position = QB的所有行.只会出现某些字段
虽然行.

像这样：

SELECT Player, Team, Pass_Yds, Pass_TDs, Int_Thrown, rush_Yds, rush_TDs, Overall_Pts, Total_Fantasy_Pts  FROM ff_projections WHERE Position = 'QB';

然后在网页上的表格中显示结果.

解决方法:

<?PHP
$con = MysqL_connect("localhost","user","password");
if (!$con)
  {
  die('Could not connect: ' . MysqL_error());
  }

MysqL_select_db("database", $con);

$result = MysqL_query("SELECT Player, Team, Pass_Yds, Pass_TDs, Int_Thrown, rush_Yds, rush_TDs, Overall_Pts, Total_Fantasy_Pts FROM ff_projections WHERE Position = 'QB' ORDER BY Pass_Yds DESC;");

while($row = MysqL_fetch_array($result))
  {
  echo $row['Player'];
  echo $row['Team'];
  ....
  }

MysqL_close($con);
?>