我已经经历了无数不同的帮助菜单和主题,但仍然存在问题.我只想将上传图像的文件路径插入MySQL数据库.我已经尝试将图像传递给变量,然后使用查询将其推送到数据库,但它无法正常工作.我的代码在下面,表单在顶部,PHP在下面:
<html>
<body>
<h1>test</h1>
<form action="insert.PHP" method="post" enctype="multipart/form-data">
Name <input type="text" name="name" /><br><br>
Description <input type="text" name="desc" /><br><br>
Price Low<input type="text" name="price_low" /><br><br>
Price High <input type="text" name="price_high" /><br><br>
<input type="hidden" name="MAX_FILE_SIZE" value="512000" />
3.Send this file: <input name="userfile" type="file" />
4.<input type="submit" value="Send File" /
<input type="submit" />
</form>
a
</body>
</html>
<html>
<?PHP
//upload image
$uploaddir = '';
$uploadfile = $uploaddir . basename($_FILES['userfile']['name']);
//end of upload image
if (move_uploaded_file($_FILES['userfile']['tmp_name'], $uploadfile)) {
echo "File is valid, and was successfully uploaded.\n";
} else {
echo "Upload Failed";
}
$con = MysqL_connect("localhost","admintest","gen");
if (!$con)
{
die('Could not connect: ' . MysqL_error());
}
MysqL_select_db("test2", $con);
$sql="INSERT INTO products (name, description, price_low, price_high)
VALUES
('$_POST[name]','$_POST[desc]','$_POST[price_low]','$_POST[price_high]')";
if (!MysqL_query($sql,$con))
{
die('Error: ' . MysqL_error());
}
echo "1 record added";
MysqL_close($con)
?>
</body>
解决方法:
除了Security issues和deprecated extension之外,您需要做的就是将文件名插入数据库.为此,请在数据库中添加“文件名”字段,然后相应地调整插入查询:
INSERT INTO products (name, description, price_low, price_high, filename)
VALUES (:name, :desc, :price_low, :price_high, :filename)
此外,您的$uploaddir变量为空,此时文件可能甚至没有保存在任何地方.要正确移动文件,请尝试以下操作:
$uploaddir = '/path/where/you/can/save/';
$rawFilename = $_FILES['userfile']['name'];
$extension = pathinfo($rawFilename, PATHINFO_EXTENSION);
$uploadfile = $uploaddir . md5($rawFilename) . '.' . $extension;
if (move_uploaded_file($_FILES['userfile']['tmp_name'], $uploadfile)) {
echo "File is valid, and was successfully uploaded.\n";
} else {
echo "Upload Failed";
}