女士们,女士们,晚上好!我试图对将发布信息的PHP发布脚本进行查询
SELECT `id`
FROM `leads`
WHERE `status` = 'Passed'
AND `campaign_id` = '22d0cf4f-0f81-28b1-d8dc-4f046bd1d8ee'
原行是
$id_query = MysqL_query("SELECT `id` FROM `leads` WHERE `status` = 'Passed' AND 'campaign_id' = '22d0cf4f-0f81-28b1-d8dc-4f046bd1d8ee'");
$id = MysqL_fetch_row($id_query);
echo $id[0];
BETWEEN (current_date - "DateField") > 365.0 * 65.0
但显然这是行不通的.我正在研究使用JOIN并添加
AND 'datesubmitted_c' BETWEEN Date_Add(curDate(), INTERVAL -65 YEARS) AND curDate()'
$id_query = MysqL_query("SELECT `id` FROM `leads` WHERE `status` = 'Passed' AND 'campaign_id' = '22d0cf4f-0f81-28b1-d8dc-4f046bd1d8ee' AND 'datesubmitted_c' BETWEEN Date_Add(curDate(), INTERVAL -65 YEARS) AND curDate()'");
不确定使用联接是否合适?
解决方法:
我认为您正在寻找DATE_ADD
方法,因此可以在一个范围之间进行检查.就像是:
SELECT *
FROM mytable
WHERE _condition_1_
AND date_column BETWEEN CURDATE() AND DATE_ADD(CURDATE(), INTERVAL 65 YEAR)