PHP-警告：在中为foreach()提供了无效的参数

$results = MysqL_query("select * from classpics");

foreach($results as $uno) {
    echo '<td valign="middle" align="center"><a class="neutral" href="../images.PHP?id=' . $uno['id'] . '"><img src="'. $uno['thumbs'].'" border="0" /></a>';
}

解决方法:

MysqL_query返回一个resource id,您应该获取一个数组：

$results = MysqL_query("select * from classpics");

while($row = MysqL_fetch_array($results)){
  echo '<td valign="middle" align="center"><a class="neutral" href="../images.PHP?id=' . $row['id'] . '"><img src="'. $row['thumbs'].'" border="0" /></a>';
}