我已经阅读了许多其他有关此确切问题的线索,但由于某种原因我无法解决我的问题.确实需要一些帮助.
if (!$username||!$password||!$email)
echo "Please fill out all fields";
else
{
//encrypt password
$password = md5($password);
//check if username already taken
$check = MysqL_query("SELECT * FROM Test WHERE username = '$username'");
if (MysqL_num_rows($check)>=1)
echo "Username already taken";
else
它说
Warning: MysqL_num_rows() expects parameter 1 to be resource, string
given in /Users…..
if(MysqL_num_rows($check)> = 1)这行..但是当我在PHPmyadmin中运行它时,它会向我返回结果.
请帮忙
解决方法:
更改:
$check = MysqL_query("SELECT * FROM Test WHERE username = '$username'");
至
$check = MysqL_query("SELECT * FROM Test WHERE username = '$username'") or die(MysqL_error());